Question

我在pictureBox中制作了一个强度计。为了制作这种强度计，我使用了一张照片作为Dialer（Dialer.bmp）并使用一条线制作针。我是用openCV做的。并且更改了针指针，我们在表单加载时创建了一个线程。代码如下

private: System::Void FocusExposure_Load(System::Object^  sender, System::EventArgs^  e) {
 if(ExposureThreadStatus)
                     th->Abort();
                 th = gcnew Thread(gcnew ThreadStart(this,&FocusExposure::UpdateIntensity)); 
                th->Start();
                ExposureThreadStatus = true;
                }


void UpdateIntensity()
{
Intensity_Values data;
 while(1)
 {

 data = ReadImage(focusBuffer);
    System::Drawing::Bitmap ^bmp=drawImageMeter(data.Max);
     this->pictureBox1->Image =this->pictureBox1->Image->FromHbitmap(bmp->GetHbitmap());
     delete bmp;
     Sleep(1000);                   
 }
}

 System::Drawing::Bitmap^ drawImageMeter(float intensity_value)
{
        IplImage  *Background =cvLoadImage("Dialer.bmp", 1);
        int width,height;
        if(counter==1)
        {
        width=Background->width;
           height=Background->height;
            counter++;
        needle_center.x=width/2;
        needle_center.y=height/2;
        needle_top.x=needle_center.x;
        needle_top.y=needle_center.y-140;
        }
            double const PI = 3.14159265358979323;
           int x1 = needle_top.x; 
           int y1 = needle_top.y;
           int x0=needle_center.x;
           int y0=needle_center.y;
           float angle;
            CurrIntensity = intensity_value;
            angle = CurrIntensity-PreIntensity;
            angle= 0.0703125f * angle;
           // degrees, not radians
           float radians = angle * (PI / 180.0f);   // convert degrees to radians

           if (current_max==1)
            {
                current_max++;
                int N1x1 = needle_top.x; 
                int N1y1 = needle_top.y;
                needle1_top.x = ((N1x1-x0) * cos(radians)) - ((N1y1-y0) * sin(radians)) + x0; 
                needle1_top.y = ((N1x1-x0) * sin(radians)) + ((N1y1-y0) * cos(radians)) + y0;
            }
           needle_top.x = ((x1-x0) * cos(radians)) - ((y1-y0) * sin(radians)) + x0; 
           needle_top.y = ((x1-x0) * sin(radians)) + ((y1-y0) * cos(radians)) + y0;

           cvLine(Background, needle_center, needle1_top, CV_RGB(0, 0, 255), 1, 4, 0);
           cvLine(Background, needle_center, needle_top, CV_RGB(255, 0, 0), 1, 4, 0);
         System::Drawing::Bitmap ^bmp = gcnew System::Drawing::Bitmap(Background->width,Background->height,Background->widthStep,System::Drawing::Imaging::PixelFormat::Format24bppRgb,(System::IntPtr)Background->imageData);
         PreIntensity = CurrIntensity;
         return bmp;

}

此代码工作正常，并根据我的要求提供输出。但唯一的问题是，当我打开表单时它会给内存泄漏。我在任务管理器中看到过并且还使用了英特尔Vtune分析器。此分析器在以下行显示不匹配的分配/取消分配

IplImage *Background =cvLoadImage("Dialer.bmp", 1);

我们需要重新加载此图像，因为我们在图像上绘制线条，当针指针发生变化时，它需要没有针的拨号器图像。

任何人都可以建议我解决此内存泄漏问题的任何解决方案。

任何帮助将不胜感激。

Answer 1

drawImageMeter()似乎不止一次被调用。问题是每次执行cvLoadImage()时，它都会在HEAP上为像素分配空间。因此，在显示图像后，您应该使用cvReleaseImage()将其释放，以便释放数据。

快速而肮脏（又可怕）的修复将是make the variablestatic：

static IplImage* Background =cvLoadImage("Dialer.bmp", 1);

但您应该更改应用程序的设计，以便Background仅分配一次。为此，您可以将其设为全局变量并将其加载到main()方法上，或将其设为drawImageMeter()的参数：

System::Drawing::Bitmap^ drawImageMeter(IplImage* Background, float intensity_value)
{
   // code
}

cvLoadImage函数中的内存泄漏

1 个答案: