seekbar拇指位置不等于进度

Question

我想用拇指创建不会改变进度的搜索栏。我的搜索栏的进度必须与拇指位置分开设置。我该怎么办？

我应该说，我必须扩展Seekbar并覆盖一些方法。但我不明白哪个???哪种方法决定拇指的位置？哪个是决定进步？

Please help me!!
Thanks at advance!

Answer 1

尝试使用不同的drawbles 让我举个例子：

您的code 的.java

import android.os.Bundle;
import android.app.Activity;
import android.graphics.drawable.Drawable;
import android.widget.SeekBar;

public class MainActivity extends Activity {
    private SeekBar seekBar1;

    private SeekBar seekBar2;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
         seekBar1 = (SeekBar) findViewById(R.id.seekBar1);
         seekBar2 = (SeekBar) findViewById(R.id.seekBar2);
         seekBar1.setProgress(15);
         seekBar2.setProgress(55);
         Drawable ii = getResources().getDrawable(R.drawable.ii);
        // Drawable iii = getResources().getDrawable(R.drawable.ii);
         seekBar1.setThumb(ii);
         seekBar2.setThumb(ii);

    }



}

你的问题：

你可以做的是simple只需重命名相同的drawable：

import android.os.Bundle;
import android.app.Activity;
import android.graphics.drawable.Drawable;
import android.widget.SeekBar;

public class MainActivity extends Activity {
    private SeekBar seekBar1;

    private SeekBar seekBar2;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
         seekBar1 = (SeekBar) findViewById(R.id.seekBar1);
         seekBar2 = (SeekBar) findViewById(R.id.seekBar2);
         seekBar1.setProgress(15);
         seekBar2.setProgress(55);
         Drawable ii = getResources().getDrawable(R.drawable.ii);
         Drawable iii = getResources().getDrawable(R.drawable.ii);
         seekBar1.setThumb(ii);
         seekBar2.setThumb(iii);

    }



}

这就是结果：

希望有所帮助!! :)