Question

说我有以下树：

CREATE TABLE Tree(Id int, ParentId int, Name varchar(20), Level int)

INSERT INTO Tree(Id, ParentId, Name, Level)
SELECT 1, NULL, 'Bob', 0 UNION ALL 
SELECT 2, 1, 'John', 1 UNION ALL
SELECT 3, 1, 'Bill', 1 UNION ALL
SELECT 4, 3, 'Peter', 2 UNION ALL
SELECT 5, 4, 'Sarah', 3

我需要一个脚本来查找特定级别的给定节点的祖先：

例如，2级Sarah的祖先是Peter，而0级的Peter的祖先是Bob。

使用分层CTE有一种简单的方法吗？ sqlfiddle

Answer 1

你可以这样做：

;WITH TreeCTE
AS
(
    SELECT Id, ParentId, Name, Level
    FROM Tree
    WHERE Id = 5
    UNION ALL 
    SELECT t.Id, t.ParentId, t.Name, t.Level
    FROM TreeCTE AS c
    INNER JOIN Tree t ON c.ParentId = t.Id  
)
SELECT * FROM TreeCTE;

这将为您提供从Sarah开始的父子链，其中id = 5以parentid = NULL为最高父级结尾。

这是the updated sql fiddle

Answer 2

declare @fromid int, @level int
select @fromid = 5, @level = 2 -- for sarah's ancestor at level 2
select @fromid = 4, @level = 0 -- for peter's ancestor at level 0

;with cte as (    
    select * from tree where id = @fromId
    union all
    select t.Id, t.ParentId, t.Name, t.Level from cte
        inner join tree t on t.id = cte.ParentId
) 
    select * from cte
    where Level=@level

Answer 3

试试这个：

DEclare @level int=0
Declare @name varchar(10)='Peter'
;WITH CTE as (
select * from tree where Name=@name
UNION ALL
select t.* from Tree t inner join CTE c on
t.ID=c.ParentId and t.Level >=@level)
select top 1 Name as Ancestor from CTE order by id

SQL Tree在特定级别查找祖先

3 个答案: