Question

我一直在努力调试此异常：Exception in thread "AWT-EventQueue-0" java.lang.ArrayIndexOutOfBoundsException: 1

这是我的代码

package com.Homework.Table;

import java.awt.BorderLayout;
import java.awt.Container;
import javax.swing.JFrame;
import javax.swing.JScrollPane;
import javax.swing.JTable;

public class ArrayTable  {
    static String [][] records;

    public static void main(String [] args)
    {
        String [] columns= { "col1", "col2", "col3","col4" };
        String array ="A&B&1&May 8 2011 12:17AM;;E&D&5&May 8 2011 12:43AM;;F&G&5&May 8 2011 7:06AM;;H&I&1&May 14 2011 11:57PM";
        records=to2dim (array ,";;","&");
        Object rows[][] =records;
        JFrame f = new JFrame("JTable Sample");
        f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        Container content = f.getContentPane();
        JTable table = new JTable(rows, columns);
        JScrollPane scrollPane = new JScrollPane(table);
        content.add(scrollPane, BorderLayout.CENTER);
        f.setSize(300, 200);
        f.setVisible(true);
    }

    public static String [][] to2dim (String source , String outerdelim, String innerdelim) {
        String [][] result = new String [source.replaceAll ("[^" + outerdelim + "]", "").length () + 1][]; 
        int count = 0;
        for (String line : source.split ("[" + outerdelim + "]"))
        {
            result [count++] = line.split (innerdelim);
        }
        return result;
    }
}

这是我得到的回复

 Exception in thread "AWT-EventQueue-0" java.lang.ArrayIndexOutOfBoundsException: 1
at javax.swing.JTable$1.getValueAt(Unknown Source)
at javax.swing.JTable.getValueAt(Unknown Source)
at javax.swing.JTable.prepareRenderer(Unknown Source)
at javax.swing.plaf.basic.BasicTableUI.paintCell(Unknown Source)
at javax.swing.plaf.basic.BasicTableUI.paintCells(Unknown Source)
at javax.swing.plaf.basic.BasicTableUI.paint(Unknown Source)
at javax.swing.plaf.ComponentUI.update(Unknown Source)
at javax.swing.JComponent.paintComponent(Unknown Source)
at javax.swing.JComponent.paint(Unknown Source)
at javax.swing.JComponent.paintChildren(Unknown Source)
at javax.swing.JComponent.paint(Unknown Source)
at javax.swing.JViewport.paint(Unknown Source)
at javax.swing.JComponent.paintChildren(Unknown Source)
at javax.swing.JComponent.paint(Unknown Source)
at javax.swing.JComponent.paintChildren(Unknown Source)
at javax.swing.JComponent.paint(Unknown Source)
at javax.swing.JComponent.paintChildren(Unknown Source)
at javax.swing.JComponent.paint(Unknown Source)
at javax.swing.JLayeredPane.paint(Unknown Source)
at javax.swing.JComponent.paintChildren(Unknown Source)
at javax.swing.JComponent.paintToOffscreen(Unknown Source)
at javax.swing.BufferStrategyPaintManager.paint(Unknown Source)
at javax.swing.RepaintManager.paint(Unknown Source)
at javax.swing.JComponent.paint(Unknown Source)
at java.awt.GraphicsCallback$PaintCallback.run(Unknown Source)
at sun.awt.SunGraphicsCallback.runOneComponent(Unknown Source)
at sun.awt.SunGraphicsCallback.runComponents(Unknown Source)
at java.awt.Container.paint(Unknown Source)
at javax.swing.RepaintManager.paintDirtyRegions(Unknown Source)
at javax.swing.RepaintManager.paintDirtyRegions(Unknown Source)
at javax.swing.RepaintManager.seqPaintDirtyRegions(Unknown Source)
at javax.swing.SystemEventQueueUtilities$ComponentWorkRequest.run(Unknown Source)
at java.awt.event.InvocationEvent.dispatch(Unknown Source)
at java.awt.EventQueue.dispatchEvent(Unknown Source)
at java.awt.EventDispatchThread.pumpOneEventForFilters(Unknown Source)
at java.awt.EventDispatchThread.pumpEventsForFilter(Unknown Source)
at java.awt.EventDispatchThread.pumpEventsForHierarchy(Unknown Source)
at java.awt.EventDispatchThread.pumpEvents(Unknown Source)
at java.awt.EventDispatchThread.pumpEvents(Unknown Source)
at java.awt.EventDispatchThread.run(Unknown Source)

帮助我。

Answer 1

import java.awt.BorderLayout;
import java.awt.Container;
import javax.swing.JFrame;
import javax.swing.JScrollPane;
import javax.swing.JTable;
import java.util.Arrays;
public class ArrayTable  {
    static String [][] records;

    public static void main(String [] args)
    {
        String [] columns= { "col1", "col2", "col3","col4" };
        String array ="A&B&1&May 8 2011 12:17AM;;E&D&5&May 8 2011 12:43AM;;F&G&5&May 8 2011 7:06AM;;H&I&1&May 14 2011 11:57PM";
        records=to2dim (array ,";;","&");
        Object rows[][] =records;
        JFrame f = new JFrame("JTable Sample");
        f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        Container content = f.getContentPane();
        JTable table = new JTable(rows, columns);
        JScrollPane scrollPane = new JScrollPane(table);
        content.add(scrollPane, BorderLayout.CENTER);
        f.setSize(300, 200);
        f.setVisible(true);
    }

    public static String [][] to2dim (String source , String outerdelim, String innerdelim) {

        String [][] result = new String [(source.split (outerdelim)).length][];
        int count = 0;

        System.out.println("result len "+result.length);
        for (String line : source.split (outerdelim ))
            {
                result [count++] = line.split (innerdelim);
            }

        System.out.println(Arrays.deepToString(result));
        return result;
    }
}

这应该适合你。 [;;]仅匹配单个字符，因此基于此分割将在两个连续;之间添加空格。所以它应该改为;;。

Answer 2

第2行，第4行和第6行只有一列。应该是4列。

线程“AWT-EventQueue-0”中的异常java.lang.ArrayIndexOutOfBoundsException：1

2 个答案: