Question

我想使用cURL不仅可以在HTTP POST中发送数据参数，还可以上传具有特定表单名称的文件。我应该怎么做呢？

HTTP Post参数：

userid = 12345 filecomment =这是一个图像文件

HTTP文件上传：文件位置= /home/user1/Desktop/test.jpg file = image的表单名称（对应于PHP端的$ _FILES ['image']）

我认为cURL命令的一部分如下：

curl -d "userid=1&filecomment=This is an image file" --data-binary @"/home/user1/Desktop/test.jpg" localhost/uploader.php

我得到的问题如下：

Notice: Undefined index: image in /var/www/uploader.php

问题是我使用$ _FILES ['image']来获取PHP脚本中的文件。

如何相应调整cURL命令？

Answer 1

您需要使用-F选项：
-F/--form <name=content> Specify HTTP multipart POST data (H)

试试这个：

curl \
  -F "userid=1" \
  -F "filecomment=This is an image file" \
  -F "image=@/home/user1/Desktop/test.jpg" \
  localhost/uploader.php

Answer 2

将用户ID作为路径变量捕获（推荐）：

curl -i -X POST -H "Content-Type: multipart/form-data" 
-F "data=@test.mp3" http://mysuperserver/media/1234/upload/

将用户ID作为表单的一部分：

curl -i -X POST -H "Content-Type: multipart/form-data" 
-F "data=@test.mp3;userid=1234" http://mysuperserver/media/upload/

或：

curl -i -X POST -H "Content-Type: multipart/form-data" 
-F "data=@test.mp3" -F "userid=1234" http://mysuperserver/media/upload/

Answer 3

这是我的解决方案，我一直在阅读很多帖子，他们真的很有帮助。最后，我为小文件编写了一些代码，使用cURL和PHP，我认为它非常有用。

public function postFile()
{    
        $file_url = "test.txt";  //here is the file route, in this case is on same directory but you can set URL too like "http://examplewebsite.com/test.txt"
        $eol = "\r\n"; //default line-break for mime type
        $BOUNDARY = md5(time()); //random boundaryid, is a separator for each param on my post curl function
        $BODY=""; //init my curl body
        $BODY.= '--'.$BOUNDARY. $eol; //start param header
        $BODY .= 'Content-Disposition: form-data; name="sometext"' . $eol . $eol; // last Content with 2 $eol, in this case is only 1 content.
        $BODY .= "Some Data" . $eol;//param data in this case is a simple post data and 1 $eol for the end of the data
        $BODY.= '--'.$BOUNDARY. $eol; // start 2nd param,
        $BODY.= 'Content-Disposition: form-data; name="somefile"; filename="test.txt"'. $eol ; //first Content data for post file, remember you only put 1 when you are going to add more Contents, and 2 on the last, to close the Content Instance
        $BODY.= 'Content-Type: application/octet-stream' . $eol; //Same before row
        $BODY.= 'Content-Transfer-Encoding: base64' . $eol . $eol; // we put the last Content and 2 $eol,
        $BODY.= chunk_split(base64_encode(file_get_contents($file_url))) . $eol; // we write the Base64 File Content and the $eol to finish the data,
        $BODY.= '--'.$BOUNDARY .'--' . $eol. $eol; // we close the param and the post width "--" and 2 $eol at the end of our boundary header.



        $ch = curl_init(); //init curl
        curl_setopt($ch, CURLOPT_HTTPHEADER, array(
                         'X_PARAM_TOKEN : 71e2cb8b-42b7-4bf0-b2e8-53fbd2f578f9' //custom header for my api validation you can get it from $_SERVER["HTTP_X_PARAM_TOKEN"] variable
                         ,"Content-Type: multipart/form-data; boundary=".$BOUNDARY) //setting our mime type for make it work on $_FILE variable
                    );
        curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/1.0 (Windows NT 6.1; WOW64; rv:28.0) Gecko/20100101 Firefox/28.0'); //setting our user agent
        curl_setopt($ch, CURLOPT_URL, "api.endpoint.post"); //setting our api post url
        curl_setopt($ch, CURLOPT_COOKIEJAR, $BOUNDARY.'.txt'); //saving cookies just in case we want
        curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1); // call return content
        curl_setopt ($ch, CURLOPT_FOLLOWLOCATION, 1); navigate the endpoint
        curl_setopt($ch, CURLOPT_POST, true); //set as post
        curl_setopt($ch, CURLOPT_POSTFIELDS, $BODY); // set our $BODY 


        $response = curl_exec($ch); // start curl navigation

     print_r($response); //print response

}

有了这个，我们应该得到＆＃34; api.endpoint.post＆＃34;发布了以下vars。您可以使用此脚本轻松进行测试，并且应该在最后一行的函数postFile()上接收此调试。

print_r($response); //print response

public function getPostFile()
{

    echo "\n\n_SERVER\n";
    echo "<pre>";
    print_r($_SERVER['HTTP_X_PARAM_TOKEN']);
    echo "/<pre>";
    echo "_POST\n";
    echo "<pre>";
    print_r($_POST['sometext']);
    echo "/<pre>";
    echo "_FILES\n";
    echo "<pre>";
    print_r($_FILEST['somefile']);
    echo "/<pre>";
}

它应该运行良好，它们可能是更好的解决方案，但这有效，并且非常有助于理解Boundary和multipart / from-data mime如何在PHP和cURL库上工作。

Answer 4

经过多次尝试，此命令对我有用：

curl -v -F filename=image.jpg -F upload=@image.jpg http://localhost:8080/api/upload

Answer 5

如果您要上传csv等二进制文件，请使用以下格式上传文件

curl -X POST \
    'http://localhost:8080/workers' \
    -H 'authorization: eyJhbGciOiJIUzI1NiIsInR5cCI6ImFjY2VzcyIsInR5cGUiOiJhY2Nlc3MifQ.eyJ1c2VySWQiOjEsImFjY291bnRJZCI6MSwiaWF0IjoxNTExMzMwMzg5LCJleHAiOjE1MTM5MjIzODksImF1ZCI6Imh0dHBzOi8veW91cmRvbWFpbi5jb20iLCJpc3MiOiJmZWF0aGVycyIsInN1YiI6ImFub255bW91cyJ9.HWk7qJ0uK6SEi8qSeeB6-TGslDlZOTpG51U6kVi8nYc' \
    -H 'content-type: application/x-www-form-urlencoded' \
    --data-binary '@/home/limitless/Downloads/iRoute Masters - Workers.csv'

Answer 6

导致我出现此问题的原因是一个基本的用户错误-我没有在文件的路径中包括@符号，因此curl正在发布文件的路径/名称，而不是内容。因此，Content-Length的值是8，而不是测试文件中的第49条。

curl读取和发布文件时，Content-Length标头将自动计算。

curl -i -H "Content-Type: application/xml" --data "@test.xml" -v -X POST https://<url>/<uri/

... <内容长度：479 ...

将其发布在此处以帮助将来的新手。

Answer 7

以下是如何使用void setCallback(void (*pFunc)(int * pParam), int param);正确转义上传文件的任意文件名：

bash

Answer 8

作为curl的替代方案，您可以使用HTTPie，它是一种类似于CLI的cURL，适用于人类。

安装说明：https://github.com/jakubroztocil/httpie#installation

然后运行：

http -f POST http://localhost:4040/api/users username=johnsnow photo@images/avatar.jpg

HTTP/1.1 200 OK
Access-Control-Expose-Headers: X-Frontend
Cache-control: no-store
Connection: keep-alive
Content-Encoding: gzip
Content-Length: 89
Content-Type: text/html; charset=windows-1251
Date: Tue, 26 Jun 2018 11:11:55 GMT
Pragma: no-cache
Server: Apache
Vary: Accept-Encoding
X-Frontend: front623311

...

Answer 9

我知道它可以与此命令curl -F 'filename=@/home/yourhomedirextory/file.txt' http://yourserver/upload

一起使用

使用curl上传带有文件的POST数据

9 个答案: