Question

我正在尝试使用另一个数组（基于从数据库返回的行）设置空数组的值。

我尝试了一些像array_merge这样的东西，但我最后才添加到第一个数组中。

只是好奇是否有办法做到这一点，还是我需要迭代思考每个数组并合并它们？

第二个数组中可以包含1到3个数组，而第一个数组（“empty”）数组总共有3个元素。

Empty array

(
    [0] => Array
        (
            [id] => 
            [quote_id] => 
            ...
        )

    [1] => Array
        (
            [id] => 
            [quote_id] => 
            ...
        )

    [2] => Array
        (
            [id] => 
            [quote_id] => 
            ...
        )

)

数组我想从

复制数据

Array
(
    [0] => Array
        (
            [id] => 1
            [quote_id] => 1
            ...
        )

    [1] => Array
        (
            [id] => 2
            [quote_id] => 1
            ...
        )

)

我想要实现的目标

Array
(
    [0] => Array
        (
            [id] => 1
            [quote_id] => 1
            ...
        )

    [1] => Array
        (
            [id] => 2
            [quote_id] => 1
            ...
        )

      [2] => Array
        (
            [id] => 
            [quote_id] => 
            ...
        )

)

Answer 1

您可以使用array union operator^Docs：

$combined = $rows + $empty;

+ 运算符返回附加到左侧数组的右侧数组;对于存在于两个数组中的键，将使用左侧数组中的元素，并且将忽略右侧数组中的匹配元素。

Answer 2

您可以使用array_replace()，但是您必须非常小心这些键，请参阅PHP manual中的示例。

Answer 3

你可以尝试

$empty = array(
"0" => Array("id" => null,"quote_id" => null,"position" => null,"type" => null,"number" => null,"cost" => null,"total" => null),
"1" => Array("id" => null,"quote_id" => null,"position" => null,"type" => null,"number" => null,"cost" => null,"total" => null),
"2" => Array("id" => null,"quote_id" => null,"position" => null,"type" => null,"number" => null,"cost" => null,"total" => null))

;

$content = Array(
"0" => Array("id" => 1,"quote_id" => 1,"position" => 1,"type" => "dwdwdw","number" => 22,"cost" => 33.00,"total" => 726.00),
"1" => Array("id" => 2,"quote_id" => 1,"position" => 2,"type" => "dwdw","number" => 22,"cost" => 22.00,"total" => 484.00));



var_dump(array_merge($content,array_unique($empty)));

输出

array
  0 => 
    array
      'id' => int 1
      'quote_id' => int 1
      'position' => int 1
      'type' => string 'dwdwdw' (length=6)
      'number' => int 22
      'cost' => float 33
      'total' => float 726
  1 => 
    array
      'id' => int 2
      'quote_id' => int 1
      'position' => int 2
      'type' => string 'dwdw' (length=4)
      'number' => int 22
      'cost' => float 22
      'total' => float 484
  2 => 
    array
      'id' => null
      'quote_id' => null
      'position' => null
      'type' => null
      'number' => null
      'cost' => null
      'total' => null

Answer 4

试试这个，

<?php
 $result=mysql_query($query);
 $i=0;
 while($row=mysql_fetch_assoc($result)){
 $youArray[$i]['id']=$row['id'];
 $youArray[$i]['quote_id']=$row['quote_id'];
 //remaining values
 $i++;
 }
?>

使用来自一组对象php的值更新给定数组

4 个答案: