计算JSON中每个项目的出现次数

时间:2012-10-03 15:44:29

标签: javascript jquery json

我想要返回每个属性的计数。例如,我想返回每组中有多少人。因此,对于以下JSON,它将返回组1中的3个人,组3中的3个人,组16中的2个人等。

我正在寻找一个Javascript或jQuery解决方案。感谢。

任何帮助将不胜感激。

注意:我不需要帮助解析JSON。我只需要帮助找到每次事件的计数。

{
"people":[
    {"id":"0","name":"Mike Johnson","group":1},
    {"id":"1","name":"Bob Smith","group":2},
    {"id":"2","name":"Richard Thomas","group":3},
    {"id":"3","name":"Betty White","group":16},
    {"id":"4","name":"Tim Thompson","group":3},
    {"id":"5","name":"Carl Lewis","group":16},
    {"id":"6","name":"Kathy Towers","group":3},
    {"id":"7","name":"Billy Bob","group":1},
    {"id":"8","name":"Sally Bailey","group":1}
    ]
}

2 个答案:

答案 0 :(得分:3)

像某些评论所说的那样,你必须遍历“人”阵列。可以很容易地将这个“功能”转换为我所拥有的功能,这样您就可以指定要搜索的组,并获取人数。

http://jsfiddle.net/UdhRW/

var obj = {
  "people": [
    {"id":"0","name":"Mike Johnson","group":1},
    {"id":"1","name":"Bob Smith","group":2},
    {"id":"2","name":"Richard Thomas","group":3},
    {"id":"3","name":"Betty White","group":16},
    {"id":"4","name":"Tim Thompson","group":3},
    {"id":"5","name":"Carl Lewis","group":16},
    {"id":"6","name":"Kathy Towers","group":3},
    {"id":"7","name":"Billy Bob","group":1},
    {"id":"8","name":"Sally Bailey","group":1}
    ]
};

function getCount(group) {
    var count = 0;
    for (var i = 0; i < obj.people.length; i++) {
        if (obj.people[i].group == group) {
            count++;
        }
    }
    return count;
}

getCount(1);   // should return 3

如果obj不是全局的,您可以将其传递给函数,它将是这样的:

function getCount(arr, group) {
    var count = 0;
    for (var i = 0; i < arr.length; i++) {
        if (arr[i].group == group) {
            count++;
        }
    }
    return count;
}

getCount(obj.people, 1);   // should return 3

答案 1 :(得分:1)

您可以使用以下内容提取组:

> var groups = foo['people'].map(function(value, index) {return value['group']});
[1, 2, 3, 16, 3, 16, 3, 1, 1]

从那里,只需使用这些键创建一个对象:

var group_count = {};

groups.forEach(function(value, index) {
    if (value in group_count) {
        group_count[value] += 1;
    } else {
        group_count[value] = 1;
    }
});

这将为您提供一个对象,其中包含每个组的出现次数。

此外,此代码无法使用IE8及更低版本,因此您必须在网络上的某处找到forEachmap polyfill。