Question

我有2张桌子。 table1有200万条记录，table2有1100万条记录我想从table2删除table1我是如何在MySQL中执行此操作的，对于这个数据计算需要多少钱？谢谢。

Answer 1

听起来您想要删除表2中与表1中的记录匹配的所有记录。如果是这样，您可以使用子查询。我不确定你的记录数量会有多高效，但以下情况应该有效：

DELETE FROM table2 where table2.phonenumber IN (select phonenumber from table1);

Answer 2

SELECT Table2.* FROM Table2   JOIN Table1 ON Table2.phone = Table1.phone WHERE Table2.phone is not null

DELETE Table2.* FROM Table2   JOIN Table1 ON Table2.phone = Table1.phone WHERE Table2.phone is not null

Answer 3

Delete from table2
where number in (Select number from table1)

Answer 4

尝试进行连接，然后从连接中删除

SELECT tbl1.MyId FROM table1 tbl1
JOIN table2 on tbl1.phonenumber = tb2.phonenumber

然后从

中删除

如

DELETE FROM Table2 WHERE MyID IN
(SELECT tbl1.MyId FROM table1 tbl1
JOIN table2 on tbl1.phonenumber = tb2.phonenumber)

这是sql代码，不完全确定mysql中有什么变化

祝你好运！

如果存在于table1中，则从table2中删除

4 个答案: