我试图通过使用类别并覆盖canPerformAction并在复制，剪切和粘贴选择器中返回NO来禁用UIWebView中的复制/粘贴。
当我加载网页或所有其他文档格式（例如docx，pptx，rtf，txt）时，它按预期工作，但在我将PDF文档加载到UIWebView时却没有。
似乎有一些不同的机制在UIWebView中处理PDF文档，它处理/响应复制选择器，因此我无法阻止它。
我还尝试禁用UIWebView的UIScrollView的所有子视图的用户交互，这对于除PDF之外的其他文档格式都可以正常工作。
任何人都可以帮助弄清楚如何在UIWebView中为PDF文档禁用复制吗？
答案 0 :(得分：17)
好的，所以我自己也遇到了同样的问题，似乎找到了解决方案，即使它是偏袒的。
我所做的是使用UILongPressGestureRecognizer禁用可能导致复制/粘贴的长按手势。
代码：
UILongPressGestureRecognizer* longPress = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(handleLongPress:)]; // allocating the UILongPressGestureRecognizer
longPress.allowableMovement=100; // Making sure the allowable movement isn't too narrow
longPress.minimumPressDuration=0.3; // This is important - the duration must be long enough to allow taps but not longer than the period in which the scroll view opens the magnifying glass
longPress.delegate=self; // initialization stuff
longPress.delaysTouchesBegan=YES;
longPress.delaysTouchesEnded=YES;
longPress.cancelsTouchesInView=YES; // That's when we tell the gesture recognizer to block the gestures we want
[webView addGestureRecognizer:longPress]; // Add the gesture recognizer to the view and scroll view then release
[[webView scrollView] addGestureRecognizer:longPress];
[longPress release];
答案 1 :(得分：5)
这个解决方案对我有用：
方法1 - 检测自定义长按
A）创建UILongPressGestureRecogniser的子类。
B）在您的子类中包含canBePreventedByGestureRecognizer:方法，如下所示：
标题
#import <UIKit/UIKit.h>
@interface CustomLongPress : UILongPressGestureRecognizer
@end
<强>实施
#import "CustomLongPress.h"
@implementation CustomLongPress
- (BOOL)canBePreventedByGestureRecognizer:(UIGestureRecognizer*)preventedGestureRecognizer {
return NO;
}
@end
这是子类中唯一需要的代码。
C）打开包含uiwebview / pdf阅读器的视图。包括您的子类：#import "CustomLongPress.h"，然后将自定义UILongPressGestureRecogniser添加到您的UIWebView中，如下所示：
- (void)viewDidLoad
{
[super viewDidLoad];
//Load UIWebView etc
//Add your custom gesture recogniser
CustomLongPress * longPress = [[CustomLongPress alloc] initWithTarget:self action:@selector(longPressDetected)];
[pdfWebView addGestureRecognizer:longPress];
}
D）检测长按并切换UIWebView的userInteraction Off然后再打开：
-(void)longPressDetected {
NSLog(@"long press detected");
[pdfWebView setUserInteractionEnabled:NO];
[pdfWebView setUserInteractionEnabled:YES];
}
显然，这样做的原因是因为UIWebView使用自己的手势识别器捕获长按，排除了您添加的任何其他手势识别器。但是，通过向canBePreventedByGestureRecognizer:方法返回“NO”来对您的手势识别器进行子类化并防止它们被排除会覆盖默认行为。
一旦你可以检测到PDF上的长按，将userInteraction关闭然后再打开会阻止UIWebView执行其默认行为，即启动“复制/定义”UIMenu，或者，如果长按链接，则启动弹出窗口带有“复制”和“打开”操作的-up动作表。
方法2 - 捕获UIMenu NSNotification
或者，如果你只是想阻止“复制/定义”UIMenu，（但不影响长按），你可以将这一行（监听UIMenuControllerDidShowMenuNotification）添加到你的ViewDidLoad：
[[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(menuShown) name:UIMenuControllerDidShowMenuNotification object:nil];
然后使用与上面相同的userInteraction Off / On方法添加此方法：
-(void)menuShown {
NSLog(@"menu shown");
[pdfWebView setUserInteractionEnabled:NO];
[pdfWebView setUserInteractionEnabled:YES];
}
第一个方法取自：https://devforums.apple.com/thread/72521?start=25&tstart=0，第二个方法来自Stack的某处，抱歉遗忘在哪里。如果您知道，请提供。
答案 2 :(得分：3)
很棒的回答祖巴巴。我正在使用webView显示彩色和粗体文本，我遇到了同样的问题。我把你的解决方案放到一个方法中，并在我初始化webView之后调用它。我似乎不需要代表。
self.textView = [[UIWebView alloc] initWithFrame:textFrame];
[self longPress:self.textView];
- (void)longPress:(UIView *)webView {
UILongPressGestureRecognizer* longPress = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(handleLongPress)]; // allocating the UILongPressGestureRecognizer
longPress.allowableMovement=100; // Making sure the allowable movement isn't too narrow
longPress.minimumPressDuration=0.3; // This is important - the duration must be long enough to allow taps but not longer than the period in which the scroll view opens the magnifying glass
longPress.delaysTouchesBegan=YES;
longPress.delaysTouchesEnded=YES;
longPress.cancelsTouchesInView=YES; // That's when we tell the gesture recognizer to block the gestures we want
[webView addGestureRecognizer:longPress]; // Add the gesture recognizer to the view and scroll view then release
[webView addGestureRecognizer:longPress];
}
- (void)handleLongPress {
}
答案 3 :(得分：2)
如果有人需要Zubaba在Swift 3中的回答;
let longPress = UILongPressGestureRecognizer(target: self, action: #selector(handleLongPress))
longPress.allowableMovement = 100
longPress.minimumPressDuration = 0.3
longPress.delegate = self
longPress.delaysTouchesBegan = true
longPress.delaysTouchesEnded = true
longPress.cancelsTouchesInView = true
yourWebView.addGestureRecognizer(longPress)
yourWebView.scrollView.addGestureRecognizer(longPress)
func handleLongPress() {
// Show some alert to inform user or do nothing.
}
答案 4 :(得分：1)
这是对Zubaba在Swift 3中的回答的修改，最终为我消除了警告。我将作业longPress.delegate = self更改为longPress.delegate = self as? UIGestureRecognizerDelegate。
let longPress = UILongPressGestureRecognizer(target: self, action: #selector(handleLongPress))
longPress.allowableMovement = 100
longPress.minimumPressDuration = 0.3
longPress.delegate = self as? UIGestureRecognizerDelegate
longPress.delaysTouchesBegan = true
longPress.delaysTouchesEnded = true
longPress.cancelsTouchesInView = true
webView.addGestureRecognizer(longPress)
webView.scrollView.addGestureRecognizer(longPress)
webView.loadRequest(request)
答案 5 :(得分：0)
UILongPressGestureRecognizer位于UIPDFPageView中。要访问此视图，请查看“调试”菜单中的视图层次结构，当前可以在将pdf加载到Web视图后访问此视图：
let pdfPageView = myWebView.scrollview?.subviews[0]?.subviews[0]
然后删除Long Press在传入pdfPageView：
时使用此方法func removeLongPressFromView(view: UIView){
if let gestures = view.gestureRecognizers{
for gesture in gestures{
if gesture is UILongPressGestureRecognzier{
view.removeGestureRecognizer(gesture)
}
}
}
}
答案 6 :(得分：0)
寻找Xamarin.iOS解决方案。
public class ZubabaLongPressGestureRecognizer : UIKit.UILongPressGestureRecognizer
{
public ZubabaLongPressGestureRecognizer (Action<UILongPressGestureRecognizer> action)
: base (action)
{
AllowableMovement = 100;
MinimumPressDuration = 0.3;
DelaysTouchesBegan = true;
DelaysTouchesEnded = true;
CancelsTouchesInView = true;
}
}
Zubaba给出的方法可能如下：
public class RockexLongPressGestureRecognizer : UIKit.UILongPressGestureRecognizer
{
public RockexLongPressGestureRecognizer(UIKit.UIWebView webView, Action<UILongPressGestureRecognizer> action) :
base(UserInteractionAction(webView) + action)
{
}
private static Action<UILongPressGestureRecognizer> UserInteractionAction(UIKit.UIWebView webView)
{
return (UILongPressGestureRecognizer obj) =>
{
webView.UserInteractionEnabled = false;
webView.UserInteractionEnabled = true;
};
}
public override bool CanPreventGestureRecognizer(UIGestureRecognizer preventedGestureRecognizer)
{
return false;
}
}
打开/复制/取消菜单仍然显示每个PDF页面第一次长按链接。然而，在第一次长按之后，它没有正确显示该页面。这是PDF页面相关并不能让我相信有一个可用的解决方案。
Johnny Rockex的解决方案可能如下所示：
notificationToken1 = UIMenuController.Notifications.ObserveMenuFrameDidChange (Callback);
notificationToken2 = NSNotificationCenter.DefaultCenter.AddObserver(UIMenuController.DidShowMenuNotification, Callback);
和
In [1]: product = [(0, 0, 0, 0, 0), (0, 0, 0, 0, 1), (0, 0, 0, 0, 2), (0, 0, 0,
...: 0, 3), (0, 0, 0, 1, 0), (0, 0, 0, 1, 1), (0, 0, 0, 1, 2), (0, 0, 0, 1,
...: 3), (0, 0, 0, 2, 0), (0, 0, 0, 2, 1)]
In [2]: product[3][4] # get the fifth value of the fourth element of 'product'
Out[2]: 3
我无法做任何事情。通过Xamarin.iOS修复，帮助其他人做得更好
答案 7 :(得分：0)
1.ios11 iphone6 Object-C无复制/粘贴/ lookUp / share
2
viewDidLoad{
.......
[self setupExclude];
}
- (void)setupExclude{
UILongPressGestureRecognizer *longPress = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(longPG)];
longPress.minimumPressDuration = 0.2;
[self.webview addGestureRecognizer:longPress];
UITapGestureRecognizer *singleTapGesture = [[UITapGestureRecognizer alloc]initWithTarget:self action:nil];
singleTapGesture.numberOfTapsRequired = 1;
singleTapGesture.numberOfTouchesRequired = 1;
[self.webview addGestureRecognizer:singleTapGesture];
UITapGestureRecognizer *doubleTapGesture = [[UITapGestureRecognizer alloc]initWithTarget:self action:@selector(longPG)];
doubleTapGesture.numberOfTapsRequired = 2;
doubleTapGesture.numberOfTouchesRequired = 1;
[self.webview addGestureRecognizer:doubleTapGesture];
[singleTapGesture requireGestureRecognizerToFail:doubleTapGesture];
}
- (BOOL)canPerformAction:(SEL)action withSender:(id)sender{
BOOL res = [super canPerformAction:action withSender:sender];
UIMenuController.sharedMenuController.menuVisible = NO;
self.webview.userInteractionEnabled = NO;
self.webview.userInteractionEnabled = YES;
return res;
}
- (void)longPG{
UIMenuController.sharedMenuController.menuVisible = NO;
self.webview.userInteractionEnabled = NO;
self.webview.userInteractionEnabled = YES;
}
3。完成！