Question

我正在尝试加入这些陈述：

select min(len(Password)) as min, 
       max(len(Password)) as max, 
       avg(len(Password)) as avg 
FROM Customer.dbo.Password 

UNION ALL
select min(len(password2)) as min, 
       max(len(password2)) as max, 
       avg(len(password2)) as avg 
FROM website.dbo.password2

对于这些：

SELECT c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName, o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName, 'website' db FROM website.sys.all_columns as c INNER JOIN website.sys.all_objects o ON c.object_id = o.object_id WHERE c.name like '%password%' AND type = 'U'

UNION
SELECT c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName, o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName, 'Customer' db FROM Customer.sys.all_columns as c INNER JOIN Customer.sys.all_objects o ON c.object_id = o.object_id WHERE c.name like '%password%' AND type = 'U'

他们没有共同的列。前两个SELECT语句生成三列min，max和avg密码长度，后两个生成密码所在的colName，tableName和db名称。

我想纯粹出于视觉原因在一个表中显示两个结果集，以获得相应的minName，max，avg到相应的colName，tableName和db。

我试过这样做：

DECLARE @numberTable TABLE (link nvarchar(500), max int, min int, avg int)
INSERT INTO @numberTable

select 'link', min(len(Password)) as min, 
       max(len(Password)) as max, 
       avg(len(Password)) as avg 
FROM Customer.dbo.Password UNION ALL
select 'link', min(len(password2)) as min, 
       max(len(password2)) as max, 
       avg(len(password2)) as avg 
FROM website.dbo.password2

SELECT * FROM @numberTable ORDER BY max

DECLARE @myTable TABLE (link nvarchar(500), colName nvarchar(500), tableName   nvarchar(500), db nvarchar(500))
INSERT INTO @myTable

SELECT 'link', c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName, o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName, 'website' db FROM website.sys.all_columns as c INNER JOIN website.sys.all_objects o ON c.object_id = o.object_id WHERE c.name like '%password%' AND type = 'U' UNION

SELECT 'link', c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName, o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName, 'Customer' db FROM Customer.sys.all_columns as c INNER JOIN Customer.sys.all_objects o ON c.object_id = o.object_id WHERE c.name like '%password%' AND type = 'U' 

SELECT * FROM @myTable ORDER BY db

SELECT link
FROM @myTable
LEFT OUTER JOIN @numberTable
ON @myTable.link = @numberTable.link

不幸的是，这不起作用。

我正在使用Microsoft SQL Server 2008。

希望我所追求的是有道理的。

Answer 1

您可以使用cross join加入两个不相关的表：

SELECT  c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName
,       o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName
,       'website' db 
,       pwd.[min]
,       pwd.[max]
,       pwd.[avg]
FROM    website.sys.all_columns as c 
INNER JOIN 
        website.sys.all_objects o 
ON      c.object_id = o.object_id 
CROSS JOIN
        (
        select min(len(Password)) as min, 
               max(len(Password)) as max, 
               avg(len(Password)) as avg 
        FROM   website.dbo.Password        
        ) as pwd
WHERE   c.name like '%password%' 
        AND type = 'U' 

UNION

SELECT  c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName
,       o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName
,       'Customer' db 
,       pwd.[min]
,       pwd.[max]
,       pwd.[avg]
FROM    Customer.sys.all_columns as c 
INNER JOIN 
        Customer.sys.all_objects o 
ON      c.object_id = o.object_id 
CROSS JOIN
        (
        select min(len(Password)) as min, 
               max(len(Password)) as max, 
               avg(len(Password)) as avg 
        FROM    Customer.dbo.Password        
        ) as pwd
WHERE   c.name like '%password%' 
        AND type = 'U'

Answer 2

创建他们共同拥有的任意内容并加入

Select * 
from
(
select 
       1 as RowID,
       min(len(Password)) as min,  
       max(len(Password)) as max,  
       avg(len(Password)) as avg  
FROM Customer.dbo.Password  

UNION ALL 
select 
       2,
       min(len(password2)) as min,  
       max(len(password2)) as max,  
       avg(len(password2)) as avg  
FROM website.dbo.password2 
) t1
inner join
(


SELECT 1 as RowID, c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName, o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName, 'website' db FROM website.sys.all_columns as c INNER JOIN website.sys.all_objects o ON c.object_id = o.object_id WHERE c.name like '%password%' AND type = 'U' 

UNION 
SELECT 2, c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName, o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName, 'Customer' db FROM Customer.sys.all_columns as c INNER JOIN Customer.sys.all_objects o ON c.object_id = o.object_id WHERE c.name like '%password%' AND type = 'U' 
) t2
    on t1.rowID = t2.rowID

链接两个表没有任何共同点

2 个答案: