Question

我有一个urlString：http://www.youtube.com/watch?v=5kdEhVtNFPo

我希望能够将其更改为：http://www.youtube.com/v/5kdEhVtNFPo

我该怎么做呢？我不确定是否应该使用实例方法substringWithRange:或substringFromIndex:

我尝试了这个删除了第一部分，只留下了视频ID（它删除了http://www.youtube.com/watch?v=）现在我只需要将http://www.youtube.com/v/添加到字符串的开头。

NSString *newUrlString = [urlString substringFromIndex:31];

Answer 1

NSString* newUrl = [oldUrl stringByReplacingOccurrencesOfString:@"watch?v=" withString:@"v/"];

请注意，只有在URL不包含字符串“watch？v =”的更多实例时，此方法才有效。

Answer 2

我会提出一种不同的方式，可以对你提供的输入更灵活：

- (NSString) newURLStringForOldURLString:(NSString *)oldURLString
{
    NSString *newURLString = nil;
    NSURL *url = [[NSURL alloc] initWithString:oldURLString];
    NSString *query = [url query]; /* v=5kdEhVtNFPo */
    NSArray *fieldValuePairs = [query componentsSeparatedByString:@"&"];
    for (NSString *pair in fieldValuePairs) {
        NSArray *components = [pair componentsSeparatedByString:@"="];
        NSString *field = [components objectAtIndex:0];
        NSString *value = [components objectAtIndex:1];
        if ([field isEqualToString:@"v"]) {
            newURLString = [NSString stringWithFormat:@"%@://%@:%@/%@/%@", [url scheme], [url domain], [url port], field, value];
            break;
        }
    }
    [url release];
    return newURLString;
}

Answer 3

另一种选择：

NSString *str3 = @"http://www.youtube.com/watch?v=5kdEhVtNFPo";
NSString *outputString;
NSRange range = [str3 rangeOfString:@"watch?v="];
if(range.location != NSNotFound)
{
    outputString = [str3 stringByReplacingCharactersInRange:range withString:@"v/"];
    NSLog(@"%@",outputString);

}

Answer 4

要足够灵活，您可以使用NSRegularExpression：

NSString *str = @"http://www.youtube.com/watch?v=5kdEhVtNFPo";
NSString *pattern = @"((?:http:\\/\\/){0,1}www\\.youtube\\.com\\/)watch\\?v=([:alnum:]+)";
NSString *template = @"$1v/$2";
NSRegularExpression *regexp = [NSRegularExpression 
          regularExpressionWithPattern:pattern 
                               options:NSRegularExpressionCaseInsensitive 
                                 error:nil];
NSString *newStr = [regexp stringByReplacingMatchesInString:str 
          options:0 range:NSMakeRange(0, [str length]) withTemplate:template];
NSLog(@"Replaced: %@", newStr);

更改NSString的部分

4 个答案: