Question

我收到标题中描述的错误：

Unknown column 'FeedbackType' in 'where clause'

但我不明白为什么。这是我的问题：

SELECT SQL_CALC_FOUND_ROWS `Appointments`.ID, FeedbackType, FeedbackSubType 
FROM `UserFeedback`
INNER JOIN `Appointments` ON `Appointments`.ID = `UserFeedback`.Appointments_ID 
INNER JOIN `Reasons` ON `UserFeedback`.FeedbackSubType = `Reasons`.ID  
WHERE `FeedbackType` = 1  ORDER BY `Appointments`.ID ASC
LIMIT 0, 10

FeedbackType是UserFeedback表中的一列，外壳是正确的，已经多次检查过。

为了完整性，这是表模式：

CREATE TABLE IF NOT EXISTS `UserFeedback` 
(
   ID bigint(20) NOT NULL AUTO_INCREMENT,
   FeedbackType int(4) NOT NULL,
   FeedbackSubType int(4) NOT NULL,
   Notes varchar(170) NULL,
   Appointments_ID bigint(20) NOT NULL,
   IpTracking_ID bigint(20) NOT NULL,
   PRIMARY KEY (ID),
   FOREIGN KEY (Appointments_ID) REFERENCES Appointments(Id), 
   FOREIGN KEY (IpTracking_ID) REFERENCES IpTracking(Id)    
)
ENGINE=MyISAM DEFAULT CHARSET=utf8;

可能是什么问题？

[编辑]

这些变体也不起作用（因为FeedbackType不包含保留字/字符，只属于UserFeedback表）：

... WHERE UserFeedback.FeedbackType = 1
... WHERE `UserFeedback`.`FeedbackType` = 1
... WHERE FeedbackType = '1'
etc.

（我实际上看不出他们应该这么做的原因）

[编辑2]

我运行SELECT * FROM UserFeedback以确保它确实包含该列，并且我有几行，所有行都包含列（好，INSERT无误地运行。）

对于每个提到的变体，我总是会在WHERE子句中得到相同的错误。如果我省略了WHERE条款，我会得到未经过滤的结果（包括这些结果中的FeedbackType列），因此它确实令人困惑。

[解决]

出于某种原因，将WHERE查询替换为INNER JOIN内的条件将其修复为@MarinSagovac suggested in his second snippet：

SELECT SQL_CALC_FOUND_ROWS `Appointments`.ID, FeedbackType, FeedbackSubType 
FROM `Appointments`
INNER JOIN `UserFeedback` ON `Appointments`.ID = `UserFeedback`.Appointments_ID 
   AND `UserFeedback`.FeedbackType = 1
INNER JOIN `Reasons` ON `UserFeedback`.FeedbackSubType = `Reasons`.ID  
ORDER BY `Appointments`.ID ASC
LIMIT 0, 10

请注意，现在没有WHERE子句，但语义应该是相同的，对吧？并且很明显该列确实存在，因此错误消息有点误导恕我直言。

Answer 1

你在where子句中尝试过UserFeedback.FeedbackType吗？

Answer 2

尝试添加反引号：

SELECT SQL_CALC_FOUND_ROWS `Appointments`.ID, `FeedbackType`, `FeedbackSubType`
FROM `UserFeedback`
INNER JOIN `Appointments` ON `Appointments`.ID = `UserFeedback`.Appointments_ID 
INNER JOIN `Reasons` ON `UserFeedback`.FeedbackSubType = `Reasons`.ID  
WHERE `FeedbackType` = 1  ORDER BY `Appointments`.ID ASC
LIMIT 0, 10

添加了尝试：

SELECT SQL_CALC_FOUND_ROWS `Appointments`.ID, FeedbackType, FeedbackSubType 
FROM `UserFeedback`
INNER JOIN `Appointments` ON `Appointments`.ID = `UserFeedback`.Appointments_ID 
INNER JOIN `Reasons` ON `UserFeedback`.FeedbackSubType = `Reasons`.ID  
INNER JOIN `UserFeedback`.`FeedbackType` = 1  ORDER BY `Appointments`.ID ASC
LIMIT 0, 10

Answer 3

SELECT SQL_CALC_FOUND_ROWS `Appointments`.ID, UserFeedback.FeedbackType, `UserFeedback.FeedbackSubType 
FROM `UserFeedback'
INNER JOIN `Appointments` ON `Appointments`.ID = `UserFeedback`.Appointments_ID 
INNER JOIN `Reasons` ON `UserFeedback`.FeedbackSubType = `Reasons`.ID  
WHERE UserFeedback.FeedbackType = 1  ORDER BY `Appointments`.ID ASC
LIMIT 0, 10

立即尝试

Answer 4

使用myisam时的外键？

这可能就是问题

Answer 5

在WHERE子句中尝试：

WHERE UserFeedback.FeedbackType ='1'

删除字段名称中的所有引号（'）

`where`子句中的未知列

5 个答案: