Question

我的目的是在控制台C＃应用程序中连接到Active Directory（在虚拟机上运行（Win SRV 2008R2））并记下域中的所有用户名。因为我是AD的新手，所以我只是设置了连接。

现在第一件事是第一件事;

Root DomainName = frt.local

IP：192.168.x.x

用户名：admin

通过：yyyy

我已经编写了下面的代码来设置连接但是会出错。请告诉我我错过的一点。

DirectoryEntry entry = new DirectoryEntry();
entry.Path = "LDAP://192.168.x.x/dc=frt.local";
entry.Username = @"frt.local\admin";
entry.Password = "yyyy";

在指出我错过的任何帮助后，欢迎将用户名写入控制台。

亲切的问候

Answer 1

  var username = "your username";
  var password = "your password";
  var domain = "your domain";
  var ctx = new PrincipalContext(ContextType.Domain, domain, username, password);

  using (var searcher = new PrincipalSearcher(new UserPrincipal(ctx)))
  {
    foreach (var result in searcher.FindAll())
    {
      DirectoryEntry de = result.GetUnderlyingObject() as DirectoryEntry;
      Console.WriteLine("First Name: " + de.Properties["givenName"].Value);
      Console.WriteLine("Last Name : " + de.Properties["sn"].Value);
      Console.WriteLine("SAM account name   : " + de.Properties["samAccountName"].Value);
      Console.WriteLine("User principal name: " + de.Properties["userPrincipalName"].Value);
      Console.WriteLine();
    }
  }

Answer 2

Nesim的答案很好 - 一开始。但我真的没有看到使用

的任何意义或需要

DirectoryEntry de = result.GetUnderlyingObject() as DirectoryEntry;

行 - PrincipalSearcher的结果已经是UserPrincpial，你可以更容易地访问它的属性：

using (var searcher = new PrincipalSearcher(new UserPrincipal(ctx)))
{
   foreach (var result in searcher.FindAll())
   {
       UserPrincipal foundUser = result as UserPrincipal;

       if(foundUser != null)
       {
           Console.WriteLine("First Name: {0}", foundUser.GivenName);
           Console.WriteLine("Last Name : {0}", foundUser.Surname);
           Console.WriteLine("SAM account name; {0}", foundUser.SamAccountName);
           Console.WriteLine("User principal name: {0}", foundUser.UserPrincipalName);         
           Console.WriteLine();
       }
   }
}

UserPrincipal已经非常好地将最常用的属性公开为对象本身的属性 - 不需要使用DirectoryEntry的相当混乱的代码......

Active Directory连接C＃

2 个答案: