Question

我之前发布过这个问题，但需要澄清一些让每个人都更容易的事情。我正试图用JSON输出这个，而我正在做的事似乎没有用......

{
  "request": {
    "act": "user_create",
    "user_email": "newuser@example.com",
    "user_zone": "example.com"
  },
  "result": "success",
  "msg": "A message that will be displayed to the end user"
  ...
}

以下是我目前正在使用的代码：

<?php
    $array[0]=array("request"=>array("act"=>'user_create', 
                                     "user_email"=>"newuser@example.com", 
                                     "user_zone"=>"example.com"));
    $array[1]=array('result' => 'success');
    $array[2]=array('msg' => 'A message that will be displayed to the end user');
    echo json_encode($array);
?>

使用该代码我得到的输出很接近但不完全存在并且不是有效的json输出。不确定要改变什么，但这是我目前得到的：

[{"request":{"act":"user_create","user_email":"newuser@example.com","user_zone":"example.com"}},{"result":"success"},{"msg":"A message that will be displayed to the end user"}]

如果有人可以请发布我的固定PHP代码示例，这将是非常好的。在过去的几个小时里，我一直在反复弹跳测试不同的解决方案，似乎没有任何东西正好显示我需要的东西：/提前致谢！

Answer 1

试试那个..

    $array = array(
    "request" => array(
        "act"=>"user_create",
        "user_email"=>"newuser@example.com",
        "user_zone"=>"example.com"
        ),
    "result"=>"success",
    "msg"=>"A message that will be displayed to the end user"
    );
    echo json_encode($array);

Answer 2

<?php
    $array["request"]=array("act"=>'user_create', 
                                     "user_email"=>"newuser@example.com", 
                                     "user_zone"=>"example.com");
    $array["result"] = 'success';
    $array["msg"] = 'A message that will be displayed to the end user';
    echo json_encode($array);
?>

这应该适合你。

Answer 3

$array = array(
  "request" => array(
    "act"        => "user_create",
    "user_email" => "newuser@example.com",
    "user_zone"  => "example.com"
  ),
  "result" => "success",
  "msg"    => "A message that will be displayed to the end user"
  ...
);

只需将每个{}更改为array()，将每个:更改为=>，您就可以在PHP语法中获得相同的内容。

Answer 4

<?php
    $array[0]["request"] = array(
         "act"        => 'user_create', 
         "user_email" => "newuser@example.com", 
         "user_zone"  => "example.com")
    );
    $array[0]['result'] = 'success';
    $array[0]['msg'] = 'A message that will be displayed to the end user';

    ... etc. for other requests and results and msgs

    echo json_encode($array);
?>

Answer 5

这很有效。每当以JSON格式启动数组时，在PHP中创建数组。

  $array = array( // "request" array
    "request" => array( // inner array
        "act"=>"user_create",
        "user_email"=>"newuser@example.com",
        "user_zone"=>"example.com"
        ),
    "result"=>"success",
    "msg"=>"A message that will be displayed to the end user"
    );
    echo json_encode($array);

Answer 6

$array = array(
"key1" => array(
    "innerkey1"=>"innerkeyvalue1",
    "innerkey2"=>"innerkeyvalue2",
    "innerkey3"=>"innerkeyvalue3"
    ),
"key2"=>"value2",
"key3"=>"value3"
);
echo json_encode($array);

查看更多here jsone_encode

用PHP显示JSON

6 个答案: