android alphabetindexer与数字

时间:2012-10-23 09:52:36

标签: android

在Android中,如何将AlphabetIndexer与数字一起使用?下面的代码似乎不起作用

AlphabetIndexer alphabetIndexer = 
            new AlphabetIndexer(cursor, COLUMN_INDEX,"0123456789")

2 个答案:

答案 0 :(得分:2)

AlphabetIndexer似乎与数字一样正常。 我创建了一个简单的ListFragment,它结合了字符串和数字列表,对它们进行排序并在列表中显示功能快速滚动。 这也适用于只有数字的列表。

public class ListFragment extends android.support.v4.app.ListFragment {

  public static final String VALUE_COLUMN = "value_column";
  public static final String[] PROJECTION = new String[] {
      BaseColumns._ID,
      VALUE_COLUMN
  };

  @Override
  public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setListAdapter(new AlphanumericAdapter(getActivity(),
        generateDataCursor(getSortedListOfEntries())));
  }

  @Override
  public void onViewCreated(View view, Bundle savedInstanceState) {
    super.onViewCreated(view, savedInstanceState);
    getListView().setFastScrollAlwaysVisible(true);
    getListView().setFastScrollEnabled(true);
  }

  private Cursor generateDataCursor(ArrayList<String> entriesAsArrayList) {
    MatrixCursor entriesAsCursor = new MatrixCursor(PROJECTION);
    for (String entry : entriesAsArrayList) {
      entriesAsCursor.addRow(new String[] { "0", entry });
    }
    return entriesAsCursor;
  }

  private ArrayList<String> getSortedListOfEntries() {
    ArrayList<String> listEntries = new ArrayList<String>();
    for (Locale locale : Locale.getAvailableLocales()) {
      int randomIntegerBetweenZeroAndNine = (int) (Math.random() * 10);
      listEntries.add(String.valueOf(randomIntegerBetweenZeroAndNine));
      String countryName = locale.getDisplayCountry();
      if (TextUtils.isEmpty(countryName)) listEntries.add(countryName);
    }
    Collections.sort(listEntries);
    return listEntries;
  }

  private class AlphanumericAdapter extends SimpleCursorAdapter implements SectionIndexer {

    private final AlphabetIndexer mAlphabetIndexer;

    public AlphanumericAdapter(Context context, Cursor cursor) {
      super(context, android.R.layout.simple_list_item_1, cursor, new String[] { VALUE_COLUMN }, new int[] { android.R.id.text1 });
      mAlphabetIndexer = new AlphabetIndexer(cursor, 1, "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ");
    }

    @Override
    public Object[] getSections() {
      return mAlphabetIndexer.getSections();
    }

    @Override
    public int getPositionForSection(int sectionIndex) {
      return mAlphabetIndexer.getPositionForSection(sectionIndex);
    }

    @Override
    public int getSectionForPosition(int position) {
      return mAlphabetIndexer.getSectionForPosition(position);
    }
  }
}

答案 1 :(得分:0)

你在谈论什么样的数字范围?只有0-9?否则,我不确定那会做你想要的,因为按字母顺序00000000可能会继续1111111和22222222或2222.你应该自己实现节索引器界面,这是一个非常简单的界面:http://developer.android.com/reference/android/widget/SectionIndexer.html你可以返回部分范围如“0-99”。但是如果你真的只想要数字0-9,那么你可以使用一个简单的CursorWrapper来使用AlphabetIndexer,它返回Cursor中数字的字符串值。 http://developer.android.com/reference/android/database/CursorWrapper.html

注意:这假设您的光标返回数字/非字符串类型。

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