Question

我有以下型号：

class Model_User extends ORM {

    protected $_primary_key = 'name';

    protected $_has_many = array(
        'repositories' => array(
            'model' => 'repository',
            'through' => 'repository_user',
        ),
    );
}

class Model_Repository extends ORM {

    protected $_primary_key = 'name';

    protected $_has_many = array(
        'users' => array(
            'model' => 'user',
            'through' => 'repository_user',
        ),
    );
}

我使用以下代码获取未连接到存储库的所有用户：

$repository = ORM::factory( 'repository', $this->request->param('svn_name') );
$users = ORM::factory('user')->where( 'name', 'NOT IN', $repository->users->find_all()->as_array() )
            ->find_all();

不幸的是，如果没有用户连接到特定的存储库，我会收到以下错误消息：

Database_Exception [ 1064 ]: You have an error in your SQL syntax; check the manual
 that corresponds to your MySQL server version for the right syntax to use near     
')' at line 1 [ SELECT `user`.* FROM `users` AS `user` WHERE `name` NOT IN () ]

如何在不使用if并仅使用Kohana-Methods的情况下解决此问题？

Answer 1

问题是$repository->users->find_all()->as_array()返回一个空数组，因此您的SQL查询无效（NOT IN () - ＆gt;语法无效）。
在应用where where条件之前，你应该检查数组是否为空：

$repository = ORM::factory( 'repository', $this->request->param('svn_name') );
$names = $repository->users->find_all()->as_array();
$users = ORM::factory('user');

// Check against empty names
if (!empty($names))
{
   $users->where( 'name', 'NOT IN', $names );
}

// Execute the query
$users->find_all();

“不在”Kohana ORM

1 个答案: