Question

我想创建一个if语句，在用户点击提交时将特定内容插入到MySQL数据库中。但由于某些原因它不起作用我认为我的if语句是错误的，但我不知道如何说出来。 if($_POST and $_POST['action'] == 'submit'){我如何正确地将其设置为使得如果用户按下提交，则将其插入到数据库中？

if($_POST and $_POST['action'] == 'submit'){ 
    foreach($_POST as $k=>$v){
        $$k = $v;
    }
    foreach($cat as $k=>$v){
        if($v =='') continue;
        dbConnect("INSERT INTO twit_info(cat_id) values('". $v ."')");
    }
}

以下是我的代码的提交部分。

<form id="add_tweet_form" action="<?=$u?>admin/submit.php" enctype="multipart/form-data" method="post">
<input type="hidden" value="<?=$user_info->id_str?>" name="twitid">
</form>
<form id="go_back_to_user" action="submit" method="post">
<input type="hidden" value="masud" name="username">
<input type="hidden" value="from_tweet" name="submit_username">
</form>
<nav>
<a class="btn float-right" onclick="document.forms['add_tweet_form'].submit();this.innerHTML='Submitting...';" href="javascript:;">Submit</a>
<a class="float-right nav-text gray" title="Don't submit tweet, and go back"  onclick="window.location.href='<?=$u?>admin/submit.php';" href="javascript:;">Cancel</a>

Answer 1

可能会这一行：

if($_POST and $_POST['action'] == 'submit'){

这样的事情：

if(isset($_POST['action']) && $_POST['action'] == 'submit'){

表格：

<form id="add_tweet_form" action="<?=$u?>admin/submit.php" enctype="multipart/form-data" method="post">
    <input type="hidden" value="<?=$user_info->id_str?>" name="twitid"/>
    <input type="hidden" value="submitted" name="PostAction" />
</form>
<form id="go_back_to_user" action="submit" method="post">
    <input type="hidden" value="masud" name="username">
    <input type="hidden" value="from_tweet" name="submit_username">
</form>
<nav>
    <a class="btn float-right" onclick="document.forms['add_tweet_form'].submit();this.innerHTML='Submitting...';" href="javascript:;">Submit</a>
    <a class="float-right nav-text gray" title="Don't submit tweet, and go back"  onclick="window.location.href='<?=$u?>admin/submit.php';" href="javascript:;">Cancel</a>

进展：

if($_POST['PostAction']) && $_POST['PostAction'] == 'submitted'){ 
    echo '<pre>';
    print_r($_POST); // to see if the right info is posted...
    echo '</pre>';
    foreach($_POST as $k=>$v){
        $$k = $v;
    }
    foreach($cat as $k=>$v){
        if($v =='') continue;
        dbConnect("INSERT INTO twit_info(cat_id) values('". $v ."')");
        echo 'We have inserted something <br />';
    }
}

Answer 2

添加<input type="hidden" name="add_tweet_form" value="true">

然后检查if(isset($_POST['add_tweet_form']) && $_POST['add_tweet_form']=='true')

在If语句中插入DB

2 个答案: