C动态创建包含可变大小的2d数组的结构数组

Question

  

可能重复：
  How can I create a dynamically sized array of structs?

我是C的新手并且在线学习确实很有帮助，但现在我真的被卡住了。我希望有一个结构数组ACout，大小为ACcount

typedef struct{
int outcount;
int *lingoout;
double **likegoout;
} ACout;

// int outcount是数组lingoout的大小，likegoout是一个2d数组，行数为outcount，列数为4

// int outcount将被计算，并且每个ACout将有所不同。

int ACcount=0; //global, outside main

in main (){
 //HOW TO INITIALIZE THE ARRAY OF STRUCTS???
 //LIKE THIS?
  ACout* ACout_array = (ACout *) calloc (1, sizeof (ACout));
  if ( ACout_array == NULL) {
printf("Cannot allocate initial memory for data\n");
exit(1);
   }
 }

in some function {
ACcount++;
//int lingoout is computed here, as n; 
//also array lingout, as lin[n] 
//2d array likegoout, as likeout[n][4] is ready here

//how can I write a function to add one more structs to the array?
addarray(ACcount, AC_array);

//how can I put my calculated values to the structs?

 AC_array[ACcount]->outcount=n;
AC_array[ACcount]->lingoout=lin;
AC_array[ACcount]->likegoout=likeout;

}

void addACarray (ACout **ACout_array, int ACcount) {

  ACout *temp = (ACout*)realloc(*ACout_array, (ACcount * sizeof(ACout)));

  if(temp == NULL) {
    printf("Cannot allocate growarray memory!\n");
  }
  else
    *ACout_array = temp;
}

感谢您的帮助！非常感激！！！ ---海伦