Question

这是一个选择查询...

   $q = "SELECT
        tcs.tutor_id AS tid,
        tcs.category_id AS cid,
        tcs.subject_id AS sid,
        GROUP_CONCAT( DISTINCT s.subjects SEPARATOR ', ') AS subjects,
        t.tutor_name AS tname,
        t.tutor_code AS tcode,
        DATE_FORMAT(t.registration_date, '%b %D, %Y') AS date,
        t.qualification AS qualifi,
        GROUP_CONCAT( DISTINCT o.option_name SEPARATOR ', ') AS tutor_option,
        timg.image_name AS img,
        city_name AS city,
        d.district_name AS district
   FROM tutor_category_subject as tcs
        INNER JOIN subject AS s ON tcs.subject_id = s.subject_id
        INNER JOIN tutor_option AS toption ON toption.tutor_id = tcs.tutor_id
        INNER JOIN options AS o ON toption.option_id = o.option_id
        INNER JOIN tutors AS t ON tcs.tutor_id = t.tutor_id
        INNER JOIN address ON address.address_id = t.address_id
        INNER JOIN city ON city.city_id = address.city_id
        INNER JOIN district AS d ON d.district_id = city.district_id
        LEFT JOIN tutor_images AS timg ON timg.tutor_id = tcs.tutor_id AND timg.image_type = 'profile'
   WHERE s.subjects LIKE '%$subject%'
   GROUP BY tcs.tutor_id";

此查询现在正在运行..现在我发现了一个问题。这是.....很多主题可能需要一个特定的导师。我需要选择与教师有关的所有主题，并使用搜索关键字来显示搜索结果。在此查询中，搜索关键字是＆＃39; $ subject＆＃39;。此查询仅选择与给定关键字类似的导师的主题。例如，如果用户提供的关键字类似于＆＃39; business＆＃39;查询选择该导师的科目，如商业研究，商业会计等，只有＆＃39;。所以我也需要通过这个查询选择其他主题..任何人都可以帮助我吗？

谢谢你。

Answer 1

嗯，我不是MySQL大师，但我认为你不需要选择

 tcs.category_id AS cid,
 tcs.subject_id AS sid,

您还需要使用distinct关键字

SELECT distinct
    tcs.tutor_id AS tid,
    GROUP_CONCAT( DISTINCT s.subjects SEPARATOR ', ') AS subjects,
    t.tutor_name AS tname,
    t.tutor_code AS tcode,
    DATE_FORMAT(t.registration_date, '%b %D, %Y') AS date,
    t.qualification AS qualifi,
    GROUP_CONCAT( DISTINCT o.option_name SEPARATOR ', ') AS tutor_option,
    timg.image_name AS img,
    city_name AS city,
    d.district_name AS district
FROM tutor_category_subject as tcs
    INNER JOIN subject AS s ON tcs.subject_id = s.subject_id
    INNER JOIN tutor_option AS toption ON toption.tutor_id = tcs.tutor_id
    INNER JOIN options AS o ON toption.option_id = o.option_id
    INNER JOIN tutors AS t ON tcs.tutor_id = t.tutor_id
    INNER JOIN address ON address.address_id = t.address_id
    INNER JOIN city ON city.city_id = address.city_id
    INNER JOIN district AS d ON d.district_id = city.district_id
    LEFT JOIN tutor_images AS timg ON timg.tutor_id = tcs.tutor_id AND timg.image_type = 'profile'
WHERE s.subjects LIKE '%$subject%'
GROUP BY tcs.tutor_id

如何解决这个问题..选择查询

1 个答案: