Question

我有三张桌子：

客户

customer_id   first_name
1              kapil
2              rajesh

帐户

Customer_id     Account_id
1                   S1
2                   s2

收据

Recipt_id   customer_id   Account_id   Transaction_type   Amount
R1            1              s1         Deposit           40000
R2            2              s2         Deposit             300
R3            1              s1         withdrawal         2000

现在我将查询如下

select   
    c.customer_id,c.first_name,s.current_balance,s.account_id,
    (select sum(amount) 
    from receipt as r ,
        saving_account as s 
    where r.transaction_type='deposit'
        and r.account_no = s.account_id
    ) as debit,
    (select sum(amount) 
    from receipt as r ,
        saving_account as s
    where r.transaction_type='withdrawl'
        and r.account_no = s.account_id  
    )as credit 
from customer as c 
left outer join saving_account as s 
inner join receipt as r on r.customer_id = s.customer_id 
on s.customer_id = c.customer_id 
group by c.customer_id

但是它给了我一笔整行和借记的单一值我不明白为什么会这样表现出来......

我想要的结果是：

customer_id customer_name account_id debit credit balance
1           kapil         s1         40000   2000  200
2           rajesh        s2         300     null  500

Answer 1

SELECT  customer_ID, first_name, Account_ID,
        Deposit, Withdrawal, 
        (Deposit - Withdrawal) balance
FROM 
(
    SELECT  a.customer_ID, 
            a.first_name,
            b.Account_ID,
            SUM (CASE WHEN c.transaction_type = 'Deposit' THEN c.Amount ELSE 0 END) Deposit,
            SUM (CASE WHEN c.transaction_type = 'withdrawal' THEN c.Amount ELSE 0 END) Withdrawal
    FROM    customer a
            INNER JOIN Account b
                ON a.customer_ID = b.customer_ID
            LEFT JOIN Receipt c
                ON b.customer_ID = c.customer_ID AND
                    b.account_ID = c.Account_ID
    GROUP BY a.customer_ID, a.first_name, b.Account_ID
) bb

SQLFiddle Demo

Answer 2

试试这个：

select
  c.customer_id, 
  c.first_name,
  a.account_id,
  sum(case 
        when r.transaction_type='deposit' then r.Amount 
        else 0 
      end) as Debit,
  sum(case 
        when r.transaction_type='withdrawal' then r.Amount 
        else 0 
      end) as Credit,

  sum(case 
        when r.transaction_type='deposit' then r.Amount 
        else 0 
      end)-
  sum(case 
        when r.transaction_type='withdrawal' then r.Amount 
        else 0 
      end) as balance
from customer c
join account a
  on c.customer_id = a.customer_id
join Receipt r
  on a.account_id = r.account_id
group by 
  c.customer_id, 
  c.first_name,
  a.account_id

您还可以test it online。

注意：我不知道如何确定Balace，所以我只是按Debit - Credit计算出来。

Answer 3

在saving_account表上推断current_balance列：

Select
  c.customer_id,
  c.customer_name,
  s.account_id,
  sum(case when r.transaction_type = 'Deposit' Then r.Amount Else 0 End) As debit,
  sum(case when r.transaction_type = 'Withdrawal' Then r.Amount Else 0 End) as credit,
  s.current_balance
From
  customer c
    left outer join
  saving_account s
    on c.customer_id = s.customer_id
    left outer join
  receipt r
    on s.customer_id = r.customer_id and s.account_id = r.account_id
Group By
  c.customer_id,
  c.customer_name,
  s.account_id,
  s.current_balance

使用子查询的sum函数

3 个答案: