Question

我有一个消息合同，我将传递给我的wcf服务，我正在使用消息检查器，我用它来查找wcf客户端发送的内容。我有消息，但我不知道如何从中获取数据。以下是我传递给wcf服务的消息请求。

[MessageContract]
public  class MyMessageRequest
{
    [MessageBodyMember]
    public string Response
    {
        get;
        set;
    }

    [MessageHeader]
    public string ExtraValues
    {
        get;
        set;
    }
}

我收到消息的方法如下：

public object AfterReceiveRequest(ref System.ServiceModel.Channels.Message request, System.ServiceModel.IClientChannel channel, System.ServiceModel.InstanceContext instanceContext)
{
        MessageBuffer buffer = request.CreateBufferedCopy(Int32.MaxValue);

        request = buffer.CreateMessage();
        Console.WriteLine("Received:\n{0}", buffer.CreateMessage().ToString());
        return null;
}

我希望从消息中看到Response和ExtraValues的值，请有人帮我解决这个问题。

Answer 1

我在Microsoft的Message.ToString（）实现中发现了一个缺陷。然后我找出原因并找到了解决方案。

Message.ToString（）可以将Body内容设为“... stream ...”。

这意味着Message是使用从尚未读取的Stream创建的XmlRead或XmlDictionaryReader创建的。

ToString记录为不更改消息的状态。因此，他们不会阅读Stream，只需输入标记即可。

由于我的目标是（1）获取字符串，（2）更改字符串，以及（3）从更改的字符串创建新消息，我需要做一些额外的操作。

以下是我提出的建议：

/// <summary>
/// Get the XML of a Message even if it contains an unread Stream as its Body.
/// <para>message.ToString() would contain "... stream ..." as
///       the Body contents.</para>
/// </summary>
/// <param name="m">A reference to the <c>Message</c>. </param>
/// <returns>A String of the XML after the Message has been fully
///          read and parsed.</returns>
/// <remarks>The Message <paramref cref="m"/> is re-created
///          in its original state.</remarks>
String MessageString(ref Message m)
{
    // copy the message into a working buffer.
    MessageBuffer mb = m.CreateBufferedCopy(int.MaxValue);

    // re-create the original message, because "copy" changes its state.
    m = mb.CreateMessage();

    Stream s = new MemoryStream();
    XmlWriter xw = XmlWriter.Create(s);
    mb.CreateMessage().WriteMessage(xw);
    xw.Flush();
    s.Position = 0;

    byte[] bXML = new byte[s.Length];
    s.Read(bXML, 0, s.Length);

    // sometimes bXML[] starts with a BOM
    if (bXML[0] != (byte)'<')
    {
        return Encoding.UTF8.GetString(bXML,3,bXML.Length-3);
    }
    else
    {
        return Encoding.UTF8.GetString(bXML,0,bXML.Length);
    }
}
/// <summary>
/// Create an XmlReader from the String containing the XML.
/// </summary>
/// <param name="xml">The XML string o fhe entire SOAP Message.</param>
/// <returns>
///     An XmlReader to a MemoryStream to the <paramref cref="xml"/> string.
/// </returns>
XmlReader XmlReaderFromString(String xml)
{
    var stream = new System.IO.MemoryStream();
    // NOTE: don't use using(var writer ...){...}
    //  because the end of the StreamWriter's using closes the Stream itself.
    //
    var writer = new System.IO.StreamWriter(stream);
    writer.Write(xml);
    writer.Flush();
    stream.Position = 0;
    return XmlReader.Create(stream);
}
/// <summary>
/// Creates a Message object from the XML of the entire SOAP message.
/// </summary>
/// <param name="xml">The XML string of the entire SOAP message.</param>
/// <param name="">The MessageVersion constant to pass in
///                to Message.CreateMessage.</param>
/// <returns>
///     A Message that is built from the SOAP <paramref cref="xml"/>.
/// </returns>
Message CreateMessageFromString(String xml, MessageVersion ver)
{
    return Message.CreateMessage(XmlReaderFromString(xml), ver);
}

-Jesse

Answer 2

我想你想要

http://msdn.microsoft.com/en-us/library/system.servicemodel.description.typedmessageconverter.frommessage.aspx

其中一个

(new TypedMessageConverter<MyMessageRequest>()).FromMessage(msg)

将为您提供所需的对象。

如何从System.ServiceModel.Channels.Message获取消息内容？

2 个答案: