这是我的服务类
import android.app.Service;
import android.content.Intent;
import android.os.IBinder;
import android.util.Log;
public class Communicationservice extends Service {
@Override
public IBinder onBind(Intent intent) {
// TODO Auto-generated method stub
return null;
}
@Override
public void onCreate() {
super.onCreate();
Log.d("I AM Service","Service Created");
}
@Override
public void onStart(Intent intent, int startId) {
// TODO Auto-generated method stub
super.onStart(intent, startId);
}
}
Here is my Main Activity
import android.os.Bundle;
import android.app.Activity;
import android.content.Intent;
import android.util.Log;
import android.view.Menu;
public class MainActivity extends Activity {
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Log.d("flow","1");
Intent in = new Intent("com.yal.Communication.Communicationservice");
this.startService(in);
//startService(new Intent(MainActivity.this,Communicationservice.class));
Log.d("flow","2");
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
getMenuInflater().inflate(R.menu.activity_main, menu);
return true;
}
}
这是Manifest.xml
<application
android:icon="@drawable/ic_launcher"
android:label="@string/app_name"
android:theme="@style/AppTheme" >
<activity > ... </activity>
<service android:enabled="true" android:name="com.yal.Communication.Communicationservice"></service>
</application>
错误
11-02 16:34:17.939: D/flow(1390): 1
11-02 16:34:17.939: W/ActivityManager(92): Unable to start service Intent { act=com.yal.Communication.Communicationservice }: not found
11-02 16:34:17.939: D/flow(1390): 2
答案 0 :(得分:2)
你需要检查Intent-Filter。
下面代码段会帮助你。
<service android:name="com.yal.Communication.Communicationservice">
<intent-filter>
<action android:name="com.yal.Communication.Communicationservice" />
</intent-filter>
</service>
然后您可以调用此服务,如下所示。
Intent serviceIntent = new Intent("com.yal.Communication.Communicationservice");
startService(serviceIntent);
答案 1 :(得分:0)
构造函数public Intent (String action)
可用于指定操作,仅参见以下java doc:
public Intent (String action)
Create an intent with a given action. All other fields (data, type, class) are null. Note that the action must be in a namespace because Intents are used globally in the system -- for example the system VIEW action is android.intent.action.VIEW; an application's custom action would be something like com.google.app.myapp.CUSTOM_ACTION.
Parameters
action The Intent action, such as ACTION_VIEW.
对您的意图创建进行以下更改:
Intent in = new Intent(this,com.yal.Communication.Communicationservice.class);
或者在我的清单文件中指定操作:
<service android:name="com.yal.Communication.Communicationservice">
<intent-filter>
<action android:name="com.yal.Communication.Communicationservice" />
</intent-filter>
</service>