Question

我看过其他类似的问题，它们似乎与我想做的有点不同。

我有一个查询，我选择了两个计数值，我想将一个除以另一个。

这是我的工作代码：

SELECT (SELECT count(DISTINCT s.lastfirst) 
          FROM students s
          JOIN cc ON s.id = cc.studentid
          JOIN courses c on cc.course_number = c.course_number
         WHERE cc.schoolid='109'
           AND c.course_name LIKE 'AP %' 
           AND substr(cc.termid,0,1) <> '-'
           AND cc.dateenrolled BETWEEN to_date('08/01/2010','MM/DD/YYYY') AND  
               to_date('08/01/2011','MM/DD/YYYY')) as AP, 
       (SELECT count(DISTINCT s.lastfirst) 
          FROM students s
          JOIN cc ON s.id = cc.studentid
          JOIN courses c on cc.course_number = c.course_number
         WHERE cc.schoolid = '109'
           AND substr(cc.termid,0,1) <> '-'
           AND cc.dateenrolled BETWEEN to_date('08/01/2010','MM/DD/YYYY') 
           AND to_date('08/01/2011','MM/DD/YYYY')) as ttl
 FROM DUAL

这是我打破它的地方：

SELECT (SELECT count(DISTINCT s.lastfirst) 
          FROM students s
          JOIN cc ON s.id = cc.studentid
          JOIN courses c on cc.course_number = c.course_number
         WHERE cc.schoolid='109'
           AND c.course_name LIKE 'AP %' 
           AND substr(cc.termid,0,1) <> '-'
           AND cc.dateenrolled BETWEEN to_date('08/01/2010','MM/DD/YYYY') 
           AND to_date('08/01/2011','MM/DD/YYYY')) as AP, 
       (SELECT count(DISTINCT s.lastfirst) 
          FROM students s
          JOIN cc ON s.id = cc.studentid
          JOIN courses c on cc.course_number = c.course_number
         WHERE cc.schoolid = '109'
           AND substr(cc.termid,0,1) <> '-'
           AND cc.dateenrolled BETWEEN to_date('08/01/2010','MM/DD/YYYY')
           AND to_date('08/01/2011','MM/DD/YYYY')) as ttl,
      (AP / ttl) as pcnt
 FROM DUAL

有人可以告诉我正确的方法吗？

谢谢

Answer 1

最简单的答案就是除以两个值：

SELECT (SELECT count(DISTINCT s.lastfirst) 

FROM students s
JOIN cc ON s.id = cc.studentid
JOIN courses c on cc.course_number = c.course_number    
WHERE cc.schoolid='109'    
AND c.course_name LIKE 'AP %'     
AND substr(cc.termid,0,1) <> '-'    
AND cc.dateenrolled BETWEEN to_date('08/01/2010','MM/DD/YYYY') 
    AND to_date('08/01/2011','MM/DD/YYYY')) /    
(SELECT count(DISTINCT s.lastfirst)     
FROM students s
JOIN cc ON s.id = cc.studentid
JOIN courses c on cc.course_number = c.course_number       
WHERE cc.schoolid = '109'    
AND substr(cc.termid,0,1) <> '-'    
AND cc.dateenrolled BETWEEN to_date('08/01/2010','MM/DD/YYYY') 
    AND to_date('08/01/2011','MM/DD/YYYY')) as quotient

FROM DUAL

如果你想保留这些值并获得商数，你可以这样做：

SELECT AP, ttl, AP/ttl AS quotient
FROM (
SELECT (SELECT count(DISTINCT s.lastfirst) 
          FROM students s
          JOIN cc ON s.id = cc.studentid
          JOIN courses c on cc.course_number = c.course_number
         WHERE cc.schoolid='109'
           AND c.course_name LIKE 'AP %' 
           AND substr(cc.termid,0,1) <> '-'
           AND cc.dateenrolled BETWEEN to_date('08/01/2010','MM/DD/YYYY') AND  
               to_date('08/01/2011','MM/DD/YYYY')) as AP, 
       (SELECT count(DISTINCT s.lastfirst) 
          FROM students s
          JOIN cc ON s.id = cc.studentid
          JOIN courses c on cc.course_number = c.course_number
         WHERE cc.schoolid = '109'
           AND substr(cc.termid,0,1) <> '-'
           AND cc.dateenrolled BETWEEN to_date('08/01/2010','MM/DD/YYYY') 
           AND to_date('08/01/2011','MM/DD/YYYY')) as ttl
 FROM DUAL)

但是此时你也可以在调用代码而不是SQL中进行除法，因为你只是选择了一个带有两个标量值的结果行。

将一个选择结果除以另一个选择结果

1 个答案: