Question

可能重复：
  Why do I get “Resource id #4” when I apply print_r() to an array in PHP?
  How do i “echo” a “Resource id #6” from a MySql response in PHP?

为什么我在$ result中得到“资源ID＃6”？想要1或0：P

$sql = "SELECT * FROM members WHERE rchat=1 LIMIT 1";
$result = mysql_query($sql);

if (!$result) {
unlink($fn);
//$fn = $_SESSION['sess_user'].'.txt';
$fn = 'hittaingen.txt';
mysql_query("UPDATE members SET rchat=1 room='" . $_SESSION['sess_user'] . "' WHERE     user='" . $_SESSION['sess_user'] . "'");
}

else {
  //$fn = $result['room'].'.txt';
  $fn = 'hitta.txt';
  mysql_query("UPDATE members SET rchat=2 room='" . $result['room'] . "' WHERE user='" . $_SESSION['sess_user'] . "'");
  }

Answer 1

mysql_query()只返回结果对象的引用，而不是结果本身。因此，为了获得0或1，您必须首先使用例如mysql_fetch_array()

解析结果

$row = mysql_fetch_array( $result );

此外，您一定要查看PDO和mysqli，因为mysql_X()函数被标记为已弃用且通常不被认为可以安全地防止SQL注入！

为什么我得到结果$ result

1 个答案: