无法获取范围类错误的findnext属性

时间:2012-11-10 22:29:19

标签: excel excel-vba vba

我正在尝试解析Excel 2007中的报表。它基本上是会计费用例外的报告。该报告包含每种类型的异常标题的部分。从报告中删除了一些类型的例外。我正在使用Do While循环来查找每个标题,如果需要删除该部分,我会这样做。如果不需要删除任何代码,代码工作正常,但在删除一个部分后,我得到一个“无法获取Range类的FindNext属性”错误。这是我的代码:

Sub merge_All_Section_Headers()
' Description:
' The next portion macro will find and format the Tranaction Source rows in the file
' by checking each row in column A for the following text: TRANSA.  If a cell
' has this text in it, it is selected and a function called merge_text_cells
' is run, which performs concatenation of each Transaction Source header row and
' deletes the text from the rest of the cells with broken up text.
'
lastRow = ActiveSheet.UsedRange.Rows.Count + 1
Range(lastRow & ":" & lastRow).Delete

ActiveSheet.PageSetup.Orientation = xlLandscape

With ActiveSheet.Range("A:A")
   Dim searchString As String

   searchString = "TRANSA"

   'The following sets stringFound to either true or false based on whether or not
   'the searchString (TRANSA) is found or not):
   Set stringFound = .Find(searchString, LookIn:=xlValues, lookat:=xlPart)

   If Not stringFound Is Nothing Then

      firstLocation = stringFound.Address

      Do
         stringFound.Select

         lastFound = stringFound.Address

         merge_Text_Cells

         If ((InStr(ActiveCell.Text, "CHARGE FILER") = 0) And _
             (InStr(ActiveCell.Text, "CREDIT FILER") = 0) And _
             (InStr(ActiveCell.Text, "PA MIDNIGHT FINAL") = 0) And _
             (InStr(ActiveCell.Text, "BAD DEBT TURNOVER") = 0)) Then

            section_Del 'Function that deletes unwanted sections

         End If

         Range(lastFound).Select

         Set stringFound = .FindNext(stringFound)

       Loop While Not stringFound Is Nothing And stringFound.Address <> firstLocation

     End If

End With
  '-----------------------------------------------------------------------------------
  'BELOW CONTAINS THE CODE THAT WORKS:
   Sub merge_All_Section_Headers()
   ' Description:
   ' The next portion macro will find and format the Tranaction Source rows in the file
   ' by checking each row in column A for the following text: TRANSA.  If a cell
   ' has this text in it, it is selected and a function called merge_text_cells
   ' is run, which performs concatenation of each Transaction Source header row and deletes
   ' the text from the rest of the cells with broken up text.
   '
   lastRow = ActiveSheet.UsedRange.Rows.Count + 1
   Range(lastRow & ":" & lastRow).Delete

   ActiveSheet.PageSetup.Orientation = xlLandscape

   With ActiveSheet.Range("A:A")
       Dim searchString As String
       Dim arrRangesToDelete(0 To 9) As Range

       searchString = "TRANSA"

       'The following sets stringFound to either true or false based on whether or not
       'the searchString (TRANSA) is found or not):
        Set stringFound = .Find(searchString, LookIn:=xlValues, lookat:=xlPart)

        If Not stringFound Is Nothing Then

           firstLocation = stringFound.Address

           counter = 0

           Do

              stringFound.Select

              lastFound = stringFound.Address

              merge_Text_Cells

              If ((InStr(ActiveCell.Text, "CHARGE FILER") = 0) And _
                  (InStr(ActiveCell.Text, "CREDIT FILER") = 0) And _
                  (InStr(ActiveCell.Text, "PA MIDNIGHT FINAL") = 0) And _
                  (InStr(ActiveCell.Text, "BAD DEBT TURNOVER") = 0)) Then

                  firstRowOfSection = ActiveCell.Row

                  lastRowOfSection = (ActiveSheet.Range(ActiveCell.Offset(2, 1).Address).End(xlDown).Row + 2)

                  Set arrRangesToDelete(counter) = Range(firstRowOfSection & ":" & lastRowOfSection)

                  counter = counter + 1

              End If

              Range(lastFound).Select

              Set stringFound = .FindNext(stringFound)

           Loop While Not stringFound Is Nothing And stringFound.Address <> firstLocation

        End If

   End With

   For i = 0 To counter - 1

       arrRangesToDelete(i).Delete

   Next i

   Range(firstLocation).Select

End Sub

因此,数组工作并完成工作,而不会破坏任何对象。我仍然想尝试使用Union方法,看看我是否可以使用它,这也很酷!

2 个答案:

答案 0 :(得分:3)

由于StrFound中的范围对象已被销毁,您的代码会崩溃 - 因此当您申请时,Is Nothing

有几种替代方法可以提出错误处理bu Juri(如果你使用的话应该立即重置)

联盟方法

Sub UnionAPp()
Dim c As Range
Dim rng1 As Range
With Worksheets(1).Range("a1:a500")
    Set c = .Find(2, LookIn:=xlValues)
    If Not c Is Nothing Then
        firstaddress = c.Address
        Set rng1 = c
        Do
            Set c = .FindNext(c)
            Set rng1 = Union(rng1, c)
        Loop While c.Address <> firstaddress
    End If
    MsgBox "Your working range is " & rng1.Address
End With
End Sub

因此,您可以从

修改FindNext的标准Excel帮助

标准

Sub TestInit()
With Worksheets(1).Range("a1:a500")
    Set c = .Find(2, LookIn:=xlValues)
    If Not c Is Nothing Then
        firstAddress = c.Address
        Do
            c.Value = 5
            Set c = .FindNext(c)
        Loop While Not c Is Nothing And c.Address <> firstAddress
    End If
End With
End Sub

Sub TestA()
With Worksheets(1).Range("a1:a500")
    Set c = .Find(2, LookIn:=xlValues)
    If Not c Is Nothing Then
        firstAddress = c.Address
        Do
            c.Value = 5
            Set c = .FindNext(c)
            If Not c Is Nothing Then c.Clear
            'your code: If Not StrFound Is Nothing Then Call Section_Del
        Loop While Not c Is Nothing
    End If
End With
End Sub

答案 1 :(得分:0)

如果删除所有匹配项,Findnext应该出错。

一行

On Error Goto ExitLoop
应在Set stringFound = .FindNext(stringFound)之前添加

一行

ExitLoop:

应在Loop While...

之后添加