汇编程序中的插入排序不起作用

时间:2012-11-12 13:50:25

标签: linux assembly nasm insertion-sort

我必须在NASM中插入数字。我有一个生成随机数的文件,并生成二进制数字的输出文件。我的程序将其作为输入文件加载,并且应该为输出提供使用插入排序排序的数字,也是二进制形式。

我的代码:

; Template assembler source file

section .text
global _start

_start:
    ; put your code here
    mov eax, 3
    mov ebx, 0
    mov ecx, array
    mov edx, 4*32768
    int 80h
    mov [fileLength], eax   
    shr eax,2
    dec eax
    mov [number], eax



    mov ebx, 1 
    outerloop:
        mov ecx,[array + 4*ebx]
        mov [item],ecx 

        mov ecx,ebx 
        interloop:
        mov edx,ecx 
        dec edx
        mov esi, [array + 4*edx]
        cmp esi,[array + 4*ecx]     
        jb koniec 
            mov eax,[array + 4*edx]
            mov [array + 4*ecx],eax 
        loop interloop
        koniec:

    mov edx,[item]
    mov [array + 4*ecx],edx 

    inc ebx
    cmp ebx,[number] 
    jne outerloop


    mov eax, 4
    mov ebx, 1
    mov ecx, array
    mov edx, [fileLength]
    int 80h



    ; exit to linux
    mov eax,1
    mov ebx,0
    int 80h

; initialized data section
; use directives DB (byte), DW (word), DD (doubleword), DQ (quadword)
section .data

; uninitialized data section
; use directives RESB (byte), RESW (word), RESD (doubleword), RESQ (quadword)
section .bss
    fileLength resd 1   
    number resd 1   

    array resd 32768
    item resd 1

我用来编写插入排序的伪代码:

for i ← 1 to i ← length(A)-1
   {
     // A[ i ] is added in the sorted sequence A[0, .. i-1]
     // save A[i] to make a hole at index iHole
     item ← A[i]
     iHole ← i
     // keep moving the hole to next smaller index until A[iHole - 1] is <= item
     while iHole > 0 and A[iHole - 1] > item
       {
         // move hole to next smaller index
         A[iHole] ← A[iHole - 1]
         iHole ← iHole - 1
       }
     // put item in the hole
     A[iHole] ← item
   }

来源:http://en.wikipedia.org/wiki/Insertion_sort

我对它的了解非常少,我不知道出了什么问题。它有时会排序前几个数字,但其余部分没有正确排序。

1 个答案:

答案 0 :(得分:3)

您必须更改行

cmp esi, [array + 4*edx]

cmp esi, [item]

并在dec eax之前删除outerloop。它应该工作。

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