Question

我刚刚看到这在技术上可行，我唯一无法解决的错误是每次测试时都会打印出的最后一个ASCII字符，我也在不使用 名称的情况下对其进行了测试/ em> 变量，我的意思是只对ASCII中的任何小写字母进行减法32应该给我一个大写字母，它确实如此，但我很好奇为什么我得到一个额外的字符，我在屏幕上看到的显然是Û。

#include <stdio.h> main() { char name[22]; int i; fputs("Type your name ",stdout); fgets(name,22,stdin); for (i = 0; name[i] != '\0'; i = i + 1) printf("%c",(name[i])-32); /*This will convert lower case to upper */ /* using as reference the ASCII table*/ fflush(stdin); getchar(); }

Answer 1

也许字符串末尾有一个换行符。

您可以检查字符代码，以便只转换实际为小写字母的字符：

for (i = 0; name[i] != '\0'; i = i + 1) {
  char c = name[i];
  if (c => 97 && c <= 122) {
    c -= 32;
  }
  printf("%c", c);
}

Answer 2

void read_chararray(char in_array[], int* Length)
{
    int Indx = 0, Indx2 = 0, Indx3 = 0;  // int declarations for indexs of some loops
    char cinput = { 0 }, word[255] = { 0 }, word2[255] = { 0 }; // declaration of cinput and first char array before punctiation removed

    for (Indx = 0; (cinput = getchar()) != '\n'; Indx++) { // Loop for getting characters from user stop at <enter>
        word[Indx] = cinput;                    // Placing char into array while changing to lowercase
    }   
    
    Indx2 = Indx;                               // Set Indx2 to Indx for loop operation
    for (Indx = 0; Indx < Indx2; Indx++) {      // Loop to check and replace upper characters with lower
        cinput = word[Indx];
        if (cinput >= 65 && cinput <= 90) {     // If cinput is within the ASCII range 65 and 90, this indicates upper characters
            cinput += 32;                       // Add 32 to cinput to shift to the lower character range within the ASCII table
            in_array[Indx] = cinput;            // Input new value into array pointer
        }
        else if (cinput >= 97 && cinput <= 122) // scans if character are lower ASCII, places them in array irraticating punctuation and whitespce
            in_array[Indx] = cinput;            // Input remaining lower case into array pointer
    }
    
    *Length = Indx;                              // final size of array set to Length variable for future use
}

Answer 3

#include<stdio.h>

void upper(char);

void main()
{
    char ch;
    printf("\nEnter the character in lower case");
    scanf("%c", &ch);
    upper(ch);
}

void upper( char c)
{
    printf("\nUpper Case: %c", c-32);
}

转换大写字母而不用ctype.h

3 个答案: