我有一个Trip
模型,可以让许多参与者订阅特定旅行和一个所有者。参与者是在网站上注册的用户,但我也希望能够在旅行中添加“离线”用户,在网站上没有帐户的用户,以便我可以跟踪所有用户。
所有者和参与者链接到Userena用户配置文件(附带问题:可能直接链接到User
会更好吗?但是如何让full_name在内联管理员中看到选择呢?)
class Trip(models.Model):
name = models.CharField('trip name', max_length=200)
type = models.ForeignKey(Category, related_name='categories')
.
.
.
slug = models.SlugField('trip slug', max_length=100)
owner = models.ForeignKey(UserProfile, related_name='owner')
participants = models.ManyToManyField(UserProfile, blank=True, null=True, related_name='participants')
is_public = models.BooleanField("is visible?",db_index=True)
class ParticipationInline(admin.TabularInline):
model = Trip.participants.through
extra = 3
class TripAdmin(admin.ModelAdmin):
def formfield_for_dbfield(self, db_field, **kwargs):
if db_field.name in ('desc',):
return db_field.formfield(widget=TinyMCE(
attrs={'cols': 100, 'rows': 20},
mce_attrs={'external_link_list_url': reverse('tinymce.views.flatpages_link_list')},
))
return super(TripAdmin, self).formfield_for_dbfield(db_field, **kwargs)
inlines = [
ParticipationInline,
]
exclude = ('participants',)
prepopulated_fields = {"slug": ("name",)}
list_display = ('name', 'type', 'date', 'dest','owner', 'is_public')
list_filter = ['date', 'type']
search_fields = ['name', 'dest', 'desc']
date_hierarchy = 'date'
class Media:
js = ('js/tiny_mce/tiny_mce.js',
'js/tiny_mce/textareas.js',)
admin.site.register(Trip, TripAdmin)
因此,当我通过管理界面添加Trip
时,我想首先从现有注册用户中选择一个参与者,如果我在那里找不到它们,我希望能够内联添加新的'离线'参与者。实现这一目标的最佳方法是什么?
UserProfile
继承两个配置文件?Trip
中为离线用户和两个ManyToMany关系设置单独的模型?编辑。
我按照GenericRelation的建议创建OfflineUser
给Trip
:
class OfflineUser(models.Model):
first_name = models.CharField(_('first'), max_length=30)
last_name = models.CharField(_('last'), max_length=30)
...
content_type = models.ForeignKey(ContentType)
object_id = models.PositiveIntegerField()
content_object = generic.GenericForeignKey("content_type", "object_id")
class Trip(models.Model):
...
owner = models.ForeignKey(UserProfile, related_name='owner')
participants = models.ManyToManyField(UserProfile, blank=True, null=True, related_name='participants')
offline_users = generic.GenericRelation(OfflineUser)
并在添加OfflineUserInline
后,我可以将注册用户和离线用户添加到Trip
!
然后,我可以列出这两种类型的Trip
参与者:
{% if request.user.is_staff %}
<ul>
{% for participants in object.participants.all %}
<li> {{ participants.full_name }}
</li>
{% empty %}
No registered users!
{% endfor %}
{% for participants in object.offline_users.all %}
<li> {{ participants.full_name }}
</li>
{% empty %}
No offline users!
{% endfor %}
</ul>
{% endif %}
所以它起到了一定的作用,现在我有一种奇怪的感觉,我并没有完全理解Hedde的答案......
每次我想与参与者做一些事情(计算,列出等等)我需要做两次吗?
答案 0 :(得分:1)
使用contenttypes framework可以让这更容易。您可以从管理员过滤/隐藏内容类型并清理表单或在需要时覆盖保存。对于“离线”参与者,我不会创建个人资料,但会模仿,例如:
class OfflineUser(models.Model):
first_name = models.CharField(_('first name'), max_length=30)
last_name = models.CharField(_('last name'), max_length=30)
email = models.EmailField(_('e-mail address'))
# field extensions
... = generic.GenericRelation(...)
def get_profile(self):
pass
def get_full_name(self):
"""
Add some default User methods so you can call them on
the related_object without raising attribute errors
"""
full_name = u'%s %s' % (self.first_name, self.last_name)
return full_name.strip()
现在你可以做以下事情:
{{ some_model.content_object.get_profile.get_full_name }}
有很多stackoverflow和谷歌搜索结果可以帮助你,例如