Question

我将段落转换为包含许多特殊字符的单词，如

"  , "  . `

如何在nsstring中删除此字符并在nsstring中只获取字母

离 “新”到新//the special characters are change

Answer 1

NSString *unfilteredString = @"!@#$%^&*()_+|abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
NSCharacterSet *notAllowedChars = [[NSCharacterSet characterSetWithCharactersInString:@"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"] invertedSet];
NSString *resultString = [[unfilteredString componentsSeparatedByCharactersInSet:notAllowedChars] componentsJoinedByString:@""];
NSLog (@"Result: %@", resultString);

尝试这可能有助于你

Answer 2

有很多方法可以解决这个问题。例如，这是使用正则表达式的解决方案。这只是一个例子。我们不知道您要删除的所有特殊字符范围。

#import <Foundation/Foundation.h>

int main(int argc, const char * argv[])
{

    @autoreleasepool {
        NSRegularExpression *expression = [NSRegularExpression regularExpressionWithPattern:@"[,\\.`\"]"
                                                                                    options:0
                                                                                      error:NULL];
        NSString *sampleString = @"The \"new\" quick brown fox, who jumped over the lazy dog.";
        NSString *cleanedString = [expression stringByReplacingMatchesInString:sampleString
                                                                       options:0
                                                                         range:NSMakeRange(0, sampleString.length)
                                                                  withTemplate:@""];
        printf("cleaned = %s",[cleanedString UTF8String] );

    }
    return 0;
}

Answer 3

@Rostyslav Druzhchenko对@MadhuP的选定答案的每个评论：

NSString *unfilteredString = @"!@#$%^&*()_+|abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
NSCharacterSet *notAllowedChars = [[NSCharacterSet alphanumericCharacterSet] invertedSet];
NSString *escapedString = [[unfilteredString componentsSeparatedByCharactersInSet:notAllowedChars] componentsJoinedByString:@""];
NSLog (@"Result: %@", escapedString);

这是将使用alphanumericCharacterSet处理多个国家/地区字符集的答案。

Answer 4

SWIFT接受的答案（但不是SWIFTY方式）：

 let notAllowedCharactersSet = NSCharacterSet(charactersInString: "ABCDEFGHIJKLMNOPQRSTUVWXYZ").invertedSet
 let filtered = (stringToFilter.componentsSeparatedByCharactersInSet(notAllowedCharactersSet) as NSArray).componentsJoinedByString("")

Answer 5

我确信这是一个更优雅的解决方案，但对于任何试图在Swift中执行此操作的人来说，这就是我所做的，以确保用户的电话号码中没有特殊字符。

var phone = "+1 (555) 555 - 5555"
var removeChars: NSCharacterSet = NSCharacterSet(charactersInString: "1234567890").invertedSet
var charArray = phone.componentsSeparatedByCharactersInSet(removeChars)
var placeholderString = ""
var formattedPhoneNumber: String = placeholderString.join(charArray).stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceCharacterSet())

stringByTrimmingCharactersInSet可能没有必要。

删除NSString中的特殊字符

5 个答案: