Question

有没有办法使用正则表达式拆分Java String并返回反向引用数组？

举个简单的例子，假设我想提取用户名＆amp;来自简单电子邮件地址的提供者（仅限字母）。

String pattern = "([a-z]+)@([a-z]+)\\.([a-z]{3})";
String email = "user@email.com";

String[] backrefs = backrefs(email,pattern);

System.out.println(backrefs[0]);
System.out.println(backrefs[1]);
System.out.println(backrefs[2]);

这应输出

user
email
com

Answer 1

是的，使用java.util.regex包中的Pattern和Matcher类。

String pattern = "([a-z]+)@([a-z]+)\\.([a-z]{3})";
String email = "user@email.com";
Matcher matcher = Pattern.compile(pattern).matcher(email);
// Check if there is a match, and then print the groups.
if (matcher.matches())
{
    // group(0) contains the entire string that matched the pattern.
    for (int i = 1; i <= matcher.groupCount(); i++)
    {
        System.out.println(matcher.group(i));
    }
}

Java - 数组中的Regex反向引用

1 个答案: