Question

好吧，我有一个html上传表单，由.php文件（uploader.php）处理。这是一个多文件上传的代码。

因此，当它上传时，所有文件都会以其各自的文件名转到上传目录。喜欢：abc.jpg，abc2.jpg等。

但如果有人上传了一个同名文件，那么它就会对现有文件进行ovrwrite。所以我需要一个唯一的名称来上传文件。有没有办法用唯一的随机名称重命名该文件。喜欢：12545454.jpge，234324324.jpge，323453253.jpg等..

Php代码：

<?php
if (isset($_POST['Submit'])) {
$number_of_file_fields = 0;
$number_of_uploaded_files = 0;
$number_of_moved_files = 0;
$uploaded_files = array();
$upload_directory = dirname(__file__) . '/uploaded/'; //set upload directory


/**
 * we get a $_FILES['images'] array ,
 * we procee this array while iterating with simple for loop
 * you can check this array by print_r($_FILES['images']);
 */
for ($i = 0; $i < count($_FILES['images']['name']); $i++) {
    $number_of_file_fields++;
    if ($_FILES['images']['name'][$i] != '') { //check if file field empty or not
        $number_of_uploaded_files++;
        $uploaded_files[] = $_FILES['images']['name'][$i];
        if (move_uploaded_file($_FILES['images']['tmp_name'][$i], $upload_directory . 
$_FILES['images']['name'][$i])) {
            $number_of_moved_files++;
        }

    }

}
echo "Number of File fields created $number_of_file_fields.<br/> ";
echo "Number of files submitted $number_of_uploaded_files . <br/>";
echo "Number of successfully moved files $number_of_moved_files . <br/>";
echo "File Names are <br/>" . implode(',', $uploaded_files);
}
?>

Answer 1

使用uniqid()。它是为此而制造的。

Answer 2

你可以根据蠕虫的建议联合time();和session_id()或uniqid()对每个文件的名称也是一个好主意。

使用以下代码：

<?php
$target_path = "images/";

$target_path = $target_path . basename( $_FILES['uploadedfile']['name']); 

if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
    echo "The file ".  basename( $_FILES['uploadedfile']['name']). 
    " has been uploaded";
} else{
    echo "There was an error uploading the file, please try again!";
}
//$upload_directory = ''.uniqid().'_'.dirname(__file__) . '/uploaded/'; //set upload directory

$uploaded_file="".$upload_directory ."/".uniqid()."_".$_FILES['images']['name'][$i]."";

if (move_uploaded_file($_FILES['images']['tmp_name'][$i],$uploaded_file)) {
            $number_of_moved_files++;
        }
?>


<?php
if (isset($_POST['Submit'])) {
$number_of_file_fields = 0;
$number_of_uploaded_files = 0;
$number_of_moved_files = 0;
$uploaded_files = array();
$upload_directory = dirname(__file__) . '/uploaded/'; //set upload directory


/**
 * we get a $_FILES['images'] array ,
 * we procee this array while iterating with simple for loop
 * you can check this array by print_r($_FILES['images']);
 */
for ($i = 0; $i < count($_FILES['images']['name']); $i++) {
    $number_of_file_fields++;
    if ($_FILES['images']['name'][$i] != '') { //check if file field empty or not

        $uploaded_file="".$upload_directory ."".uniqid()."_".$_FILES['images']['name'][$i]."";

        $number_of_uploaded_files++;
        $uploaded_files[] = $_FILES['images']['name'][$i];
        if (move_uploaded_file($_FILES['images']['tmp_name'][$i],$uploaded_file)) {
            $number_of_moved_files++;
        }

    }

}
echo "Number of File fields created $number_of_file_fields.<br/> ";
echo "Number of files submitted $number_of_uploaded_files . <br/>";
echo "Number of successfully moved files $number_of_moved_files . <br/>";
echo "File Names are <br/>" . implode(',', $uploaded_files);
}
?>

Answer 3

您可以使用此

 $ext = pathinfo($file_name, PATHINFO_EXTENSION);
 $newfilename = substr( sha1(uniqid (rand())), 0, 10). '.'.$ext;

Php上传文件唯一名称问题

3 个答案: