Question

我有两个表，我需要从

计算数据

登录历史记录和登录尝试

一个是不包含Login Attemtps的登录历史记录表。

登录历史记录的主键是REF_ID，但也包含Customer_ID。 Login Attempts表还包括Customer_ID

我正在尝试获取特定Customer_id的登录尝试次数和登录历史记录。我已经获得了一个Customer_ID列表并将它们放在一个临时表“#a”中这是我试图用来计算的查询。

SELECT COUNT (la.customer_ID) as login_attempts FROM
LOGIN_ATTEMPTS la
JOIN LOGIN_HISTORY lh
on la.Customer_ID = lh.customer_ID
where la.customer_ID in (select Customer_ID from #a)group by la.customer_ID

我需要的结果集是Customer_ID，以及每个客户的登录尝试次数和旁边的历史记录。我尝试了几种不同的方法，并且我总是以GROUP BY或COUNT语法出错。

我也假设我可以在这里添加一个SUM函数，但我不确定如何构建它。感谢您的帮助！

Answer 1

Select customer_ID
,(Select Count(*) from LOGIN_ATTEMPTS l where l.customer_ID=a#.ID) as [LOGIN_ATTEMPTS]
,(Select Count(*) from LOGIN_HISTORY h where h.customer_ID=a#.ID) as [LOGIN_HISTORY]
from a#

并且不使用＃

Select customer_ID
,(Select Count(*) from LOGIN_ATTEMPTS l where l.customer_ID=a2.ID) as [LOGIN_ATTEMPTS]
,(Select Count(*) from LOGIN_HISTORY h where h.customer_ID=a2.ID) as [LOGIN_HISTORY]
( 
Select Distinct customer_ID from
(
select customer_ID from LOGIN_ATTEMPTS
union
select customer_ID from LOGIN_HISTORY
) a1
)a2

Answer 2

SELECT 
  COUNT (*)  AS Attempts, 
   la.Customer_ID 
FROM
  LOGIN_ATTEMPTS la
JOIN 
   LOGIN_HISTORY lh
on la.Customer_ID = lh.customer_ID
where 
   la.customer_ID in (select Customer_ID from #a)
group by 
   la.customer_ID

来自2个独立表的COUNT

2 个答案: