Question

我有一系列数组，其值从1到5.几乎每个数组都有缺失值，有些甚至没有任何值。我的目标是用0填充缺失值。所有这些数组都存储在一个多维数组中。

我的数组看起来像：

Array
(
    [1] => Array
        (
            [0] => 1
            [1] => 2
            [2] => 3
        )

    [2] => Array
        (
            [0] => 1
            [1] => 5
        )

    [3] => Array
        (
            [0] =>  (this array has no values)
        )

    [4] => Array
        (
            [0] => 1
            [1] => 2
            [2] => 3
            [3] => 4
            [4] => 5
        )

    etc...

)

应该如何：

Array
(
    [1] => Array
        (
            [0] => 1
            [1] => 2
            [2] => 3
            [3] => 0
            [4] => 0
        )

    [2] => Array
        (
            [0] => 1
            [1] => 0
            [2] => 0
            [3] => 0
            [4] => 5
        )

    [3] => Array
        (
            [0] => 0
            [1] => 0
            [2] => 0
            [3] => 0
            [4] => 0
        )

    [4] => Array
        (
            [0] => 1
            [1] => 2
            [2] => 3
            [3] => 4
            [4] => 5
        )

    etc...

)

任何帮助都会得到满足！

Answer 1

这样的事情（array_pad()不会做到这一点）。 $myArray是您的源数组。完成的数组在$result中返回：

$result = array();
foreach( $myArray as $subKey=>$subArray ) {
  for( $i=0; $i<5; $i++ ) {
    if( isset( $subArray[$i] )) {
       $result[$subKey][$i] = $subArray[$i];
    } else {
      $result[$subKey][$i] = 0;
    }
  }
}

注意，我们会复制数组。你不能就地填充阵列。

Answer 2

对于每个子数组，循环遍历数字1到5，如果该值存在，则将其键设置为小于其值的值：

$newarray = array();

foreach($arr as $key => $subarr) {
    for ($i = 1; $i <= 5; $i++) {
        if (in_array($i, $subarr)) $newarray[$key][$i - 1] = $i;
        else $newarray[$key][$i - 1] = 0;
    }
}

$newarray是您的输出，$arr是您的输入数组。

Answer 3

您可能需要注意PHP并不真正做多维数组。它只允许您将2个平面阵列关联在一起，这不是真正的多维度。

这不起作用，会产生上述结果。

$ menu [1] =“我的训练”; //不是$ menu [1] [0]

$menu[1][1] = "To Do List";
$menu[1][2] = "Catalog";
$menu[1][3] = "Self-Report";
$menu[1][4] = "Completions";

$ menu [2] =“经理”;

$menu[2][1] = "Direct Reports";
$menu[2][2] = "Incompletes";
$menu[2][3] = "Completions";

$ menu [3] =“教练”;

$menu[3][1] = "My Classes";
$menu[3][2] = "Printables";
$menu[3][3] = "Qualifications";

这确实有效。

$ menu [1] =“我的训练”; //不是$ menu [1] [0]

$submenu[1][1] = "To Do List";
$submenu[1][2] = "Catalog";
$submenu[1][3] = "Self-Report";
$submenu[1][4] = "Completions";

$ menu [2] =“经理”;

$submenu[2][1] = "Direct Reports";
$submenu[2][2] = "Incompletes";
$submenu[2][3] = "Completions";

$ menu [3] =“教练”;

$submenu[3][1] = "My Classes";
$submenu[3][2] = "Printables";
$submenu[3][3] = "Qualifications";

$子菜单仅通过第一个键编号与$ menu相关，因为$ submenu没有第一个维度值。

Answer 4

自从我编写任何PHP以来已经很多年了但这样的事情可能会让我觉得这个技巧？

for($i = 0; $i < 5; $i++)
{
  if(empty($myArray[$i])
  {
    $myArray[$i] = 0;
  }
}

填充缺少值的php数组

4 个答案: