getJSON显示[object Object]而不是实际值

时间:2012-11-24 09:06:15

标签: javascript jquery ajax json object

我有一个JSON,我需要获取此JSON并将html作为ul li列表放入。它将值作为对象获取并在html中显示[object Object]。如果我修改json然后它工作。所以在我的脚本中可能存在一些错误,我无法正常循环访问json文件。有人可以帮忙吗:

我的JSON是:

[
    {
        "us":"USA"  
    },
    {
        "fr":"FRANCE"
    },
    {
        "es":"Spain"
    },
    {
        "sa":"South Africa"
    }
]

AND JS IS

<script>
  $.getJSON('jsonfile', function(data) {
    var items = [];
    $.each(data ,function(key,val) {
      items.push('<li id="'+ key +'">' + val +'</li>');
    });
    $('<ul />' , {
      'class':'new-div',
      html:items.join('')
    }).appendTo('body');
  });
</script>

更新的JSON:

[
{
    "items":
        {
            "item":
                [
                    {
                        "id": "0001",
                        "type": "donut",
                        "name": "Cake",
                        "ppu": 0.55,
                        "batters":
                            {
                                "batter":
                                    [
                                        { "id": "1001", "type": "Regular" },
                                        { "id": "1002", "type": "Chocolate" },
                                        { "id": "1003", "type": "Blueberry" },
                                        { "id": "1004", "type": "Devil's Food" }
                                    ]
                            },
                        "topping":
                            [
                                { "id": "5001", "type": "None" },
                                { "id": "5002", "type": "Glazed" },
                                { "id": "5005", "type": "Sugar" },
                                { "id": "5007", "type": "Powdered Sugar" },
                                { "id": "5006", "type": "Chocolate with Sprinkles" },
                                { "id": "5003", "type": "Chocolate" },
                                { "id": "5004", "type": "Maple" }
                            ]
                    }


                ]
        }
}
]

1 个答案:

答案 0 :(得分:3)

你循环的data是数组,它有对象。因此,您的key将为01等,而val将是数组中该位置的对象。< / p>

您的JSON结构实际上使输出有点麻烦,因为您的每个对象只有一个属性,但属性名称因对象而异。你可以通过循环对象属性来完成它,即使它们只有一个:

var items = [];
$.each(data ,function(outerKey, outerVal) { // <== Loops through the array
  $.each(outerVal, function(key, val) {     // <== "Loops" through each object's properties
      items.push('<li id="'+ key +'">' + val +'</li>');
  });
});

...但我改变了JSON结构。例如,假设密钥是唯一的,您的原始代码将适用于此结构:

{
    "us":"USA",
    "fr":"FRANCE",
    "es":"Spain",
    "sa":"South Africa"
}