Question

可能重复：
WCF Rest Webservice with stream

我正在使用C＃开发WCF .NET Framework 4.0。

我已使用此Visual Studio模板创建此WCF：

enter image description here

我需要发送带有两个或三个参数的图像。这是我所有的OperationContract（我要求最后一个）：

[ServiceContract]
public interface IRestServiceImpl
{
    [OperationContract]
    [WebInvoke(Method = "GET",
        ResponseFormat = WebMessageFormat.Json,
        BodyStyle = WebMessageBodyStyle.Bare,
        UriTemplate = "orders/")]
    OrderContract[] allOrders();

    [OperationContract]
    [WebInvoke(Method = "POST",
        ResponseFormat = WebMessageFormat.Json,
        BodyStyle = WebMessageBodyStyle.Bare,
        UriTemplate = "filteredOrders/")]
    OrderContract[] GetOrders(IdsMessage msg);

    [OperationContract]
    [WebInvoke(Method = "POST",
        ResponseFormat = WebMessageFormat.Json,
        BodyStyle = WebMessageBodyStyle.Bare,
        UriTemplate = "completeFilteredOrders/")]
    OrderContract[] LoadCompleteFilteredOrders(IdsMessage msg);

    [OperationContract]
    [WebInvoke(Method = "POST",
        ResponseFormat = WebMessageFormat.Json,
        BodyStyle = WebMessageBodyStyle.Bare,
        UriTemplate = "saveEReports/")]
    Boolean SaveEReports(EReportContract[] eReports);

    [OperationContract]
    [WebInvoke(Method = "POST",
        ResponseFormat = WebMessageFormat.Json,
        BodyStyle = WebMessageBodyStyle.Bare,
        UriTemplate = "saveEReport/")]
    long SaveEReport(EReportContract eReport);

    [OperationContract]
    [WebInvoke(Method = "POST",
        ResponseFormat = WebMessageFormat.Json,
        BodyStyle = WebMessageBodyStyle.Bare,
        UriTemplate = "UploadPhoto/{eReportId}/{imageType}")]
    Boolean UploadPhoto(string eReportId, string imageType, Stream fileContents);
}

这是Web.config：

<configuration>
  <system.web>
    <compilation debug="true" targetFramework="4.0" />
  </system.web>
  <system.serviceModel>
    <services>
      <service name="EReportService.RestServiceImpl" behaviorConfiguration="ServiceBehaviour">
        <endpoint address="" binding="webHttpBinding" contract="EReportService.IRestServiceImpl" behaviorConfiguration="web">
        </endpoint>
      </service>
    </services>
    <bindings>
      <webHttpBinding>
        <binding maxReceivedMessageSize="2097152" maxBufferSize="2097152" transferMode="Streamed"/>
      </webHttpBinding>
    </bindings>
    <behaviors>
      <serviceBehaviors>
        <behavior name="ServiceBehaviour">
          <serviceMetadata httpGetEnabled="true"/>
          <serviceDebug includeExceptionDetailInFaults="true"/>
        </behavior>
      </serviceBehaviors>
      <endpointBehaviors>
        <behavior name="web">
          <webHttp/>
        </behavior>
      </endpointBehaviors>
    </behaviors>
    <serviceHostingEnvironment multipleSiteBindingsEnabled="true" />
  </system.serviceModel>
 <system.webServer>
    <modules runAllManagedModulesForAllRequests="true"/>
  </system.webServer>
  <connectionStrings>

  </connectionStrings>
</configuration>

当我运行服务时，我得到以下异常：

操作必须有一个类型为Stream
的参数

如果我这样做：

[OperationContract]
[WebInvoke(Method = "POST",
    ResponseFormat = WebMessageFormat.Json,
    BodyStyle = WebMessageBodyStyle.Bare,
    UriTemplate = "UploadPhoto")]
Boolean UploadPhoto(Stream fileContents);

它完美无缺，但我需要发送更多带图像的数据。

此服务适用于 Android 平板电脑应用。以下代码显示了我现在如何将图像发送到服务器：

public static Boolean sendImage(String url, String filePath)
{
    try
    {
        MultiValueMap<String, Object> formData;

        Resource resource = new FileSystemResource(filePath);

        // populate the data to post
        formData = new LinkedMultiValueMap<String, Object>();
        formData.add(OrderSpringController.FILE, resource);

        HttpHeaders requestHeaders = new HttpHeaders();
        requestHeaders.setAccept(Collections.singletonList(new MediaType("application","json")));

        // Sending multipart/form-data
        requestHeaders.setContentType(MediaType.MULTIPART_FORM_DATA);

        // Populate the MultiValueMap being serialized and headers in an HttpEntity object to use for the request
        HttpEntity<MultiValueMap<String, Object>> requestEntity = 
                new HttpEntity<MultiValueMap<String, Object>>(formData, requestHeaders);

        GsonHttpMessageConverter messageConverter = new GsonHttpMessageConverter();
        List<HttpMessageConverter<?>> messageConverters = new ArrayList<HttpMessageConverter<?>>();
        messageConverters.add(messageConverter);

        // Create a new RestTemplate instance
        RestTemplate restTemplate = new RestTemplate(true);
        restTemplate.getMessageConverters().add(messageConverter);

        // Make the network request, posting the message, expecting a String in response from the server
        ResponseEntity<Boolean> response = restTemplate.exchange(url, HttpMethod.POST, requestEntity,
                Boolean.class);

        // Return the response body to display to the user
        return response.getBody();
    }
    catch (Exception ex)
    {
        ex.printStackTrace();
    }
    return null;
}

浏览到元数据端点（http://localhost:2351/RestServiceImpl.svc）时会发生错误。

如何发送图片和参数？

Answer 1

如果切换到（BasicHttp或WSHttp）Binding，那么您可以通过组合单个数据类型来实现您的目标，包括通过属性和Stream对象本身的所有自定义参数。然后，您正在使用消息传递样式而不是RPC对话。请注意[MessageContract]系列的WCF DTO装饰器。

[ServiceContract]
public interface ITransferService
{
    [OperationContract]
    RemoteFileInfo DownloadFile(DownloadRequest request);

    [OperationContract]
    void UploadFile(RemoteFileInfo request); 
}
[MessageContract]
public class DownloadRequest
{
    [MessageBodyMember]
    public string FileName;
}

[MessageContract]
public class RemoteFileInfo : IDisposable
{
    [MessageHeader(MustUnderstand = true)]
    public string FileName;

[MessageHeader(MustUnderstand = true)]
public long Length;

[MessageBodyMember]
public System.IO.Stream FileByteStream;

public void Dispose()
{ 
    if (FileByteStream != null)
    {
        FileByteStream.Close();
        FileByteStream = null;
    }
}

}

这有必要的代码http://www.codeproject.com/Articles/166763/WCF-Streaming-Upload-Download-Files-Over-HTTP

但我强烈建议WCF: using streaming with Message Contracts和http://blogs.msdn.com/b/carlosfigueira/archive/2011/03/25/wcf-streaming-inside-data-contracts.aspx

This也是必须的：）

Answer 2

尝试重新排序您的参数，以便Stream是最后一个。

还要看here

Answer 3

我创建了新类型并将其选中

它包含3个值（stream，reportid，reporttype）

下面是代码

namespace WcfService5
{

    [ServiceContract]
    public interface IService1
    {    
        [OperationContract]
        Boolean UploadPhoto(data fileContents);
    }

    [Serializable]
    public struct data 
    {
        System.IO.Stream mystream;
        string ereport;
        string reporttype;
    }
}

这是服务代码

public class Service1 : IService1
{
    public bool UploadPhoto( data value)
    {
        return false;
    }     
}

WCF服务应用程序：操作必须具有单个参数，其类型为Stream

3 个答案: