没有使用fosUserBundle symfony2.1为帐户配置编码器

时间:2012-11-28 09:50:38

标签: submit symfony-2.1 fosuserbundle encoder

我提交连接表单时出现此错误(我使用的是FOSUserBundle最新版本):

No encoder has been configured for account "MyApp\UtilisateurBundle\Entity\Utilisateur

这是我的实体:

    <?php
namespace MyApp\UtilisateurBundle\Entity;
use FOS\UserBundle\Entity\User as BaseUser;
use Doctrine\ORM\Mapping as ORM;
/**
 * @ORM\Entity
 */
class Utilisateur extends BaseUser
{
    /**
    * @ORM\Id
    * @ORM\Column(type="integer")
    * @ORM\generatedValue(strategy="AUTO")
    */
    protected $id;
    public function __construct()
    {
        parent::__construct();
    }

    /**
     * Get id
     *
     * @return integer 
     */
    public function getId()
    {
        return $this->id;
    }
}

这是我的app / config / security.yml:

imports:
- { resource: "@MyAppFilmothequeBundle/Resources/config/security.yml" }

这是我的src / MyApp / FilmothequeBundle / Ressources / config / security.yml:

security:
providers:
    fos_userbundle:
        id: fos_user.user_manager

firewalls:
    main:
        pattern:      .*
        form_login:
            provider:       fos_userbundle
            login_path:     /myapp/login
            use_forward:    false
            check_path:     /myapp/login_check
            failure_path:   null
            default_target_path: /myapp
        logout:
            path:   /myapp/logout
            target: /myapp
        anonymous:    true

我按照本教程执行此操作:http://j-place.developpez.com/tutoriels/php/ameliorez-vos-applications-developpees-avec-symfony2/#LVI-B-1

我怎样才能做到这一点? 提前谢谢你

3 个答案:

答案 0 :(得分:39)

尝试将此添加到security.yml

中的安全密钥
encoders:
        FOS\UserBundle\Model\UserInterface: sha512

所以它是

security:
    encoders:
        FOS\UserBundle\Model\UserInterface: sha512

    providers:
        ...

    firewalls:
        ...

答案 1 :(得分:1)

您需要将此代码添加到security.yml

    encoders:
        # use your user class name here
        App\Entity\User:
            # Use native password encoder
            # This value auto-selects the best possible hashing algorithm
            # (i.e. Sodium when available).
            algorithm: auto

我使用symfony 4.4

为我工作

答案 2 :(得分:0)

我在LexikJWTAuthenticationBundle上遇到此错误。

它对我有帮助(True):

config/packages/security.yaml
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