IDataErrorInfo:如何知道所有属性是否有效?

时间:2012-11-28 10:47:57

标签: wpf idataerrorinfo validation

我有一个WPF应用程序(.Net 3.5),它使用ViewModel上的IDataErrorInfo来验证输入。

效果很好,用户控件可以获得正确的UI反馈。

问题是用户仍然可以更改所选元素,或保存此元素。

所以我的问题是:我怎么知道我所有的财产都有效?或者至少我所有显示的值都是有效的。目标是在此结果上绑定一些IsActive

3 个答案:

答案 0 :(得分:16)

从您对IDataErrorInfo实施的评论中将您的实施更改为此风格....

#region IDataErrorInfo Members

public string Error
{
    get { return this[null] }
}

public string this[string columnName]
{
    get
    {
        StringBuilder result = new StringBuilder();
        if (string.IsNullOrEmpty(columnName) || columnName == "FirstName")
        {
            if (string.IsNullOrEmpty(FirstName))
                result.Append("Please enter a First Name\n");
        }
        if (string.IsNullOrEmpty(columnName) || columnName == "LastName")
        {
            if (string.IsNullOrEmpty(LastName))
                result.Append("Please enter a Last Name\n");
        }
       if (string.IsNullOrEmpty(columnName) || columnName == "Age")
        {
            if (Age < = 0 || Age >= 99)
                result.Append("Please enter a valid age\n");
        }
        return (result.Length==0) ? null : result.Remove(result.Length-1,1).ToString();
    }
}

#endregion


public bool IsValid {
   get { return string.IsNullOrEmpty(this.Error); }
}

然后在你的财产改变事件

if (e.PropertyName == "Error") {
   OnPropertyChanged(this,new PropertyChangedEventArgs("IsValid"));
}
if (e.PropertyName != "Error" && e.PropertyName != "IsValid") {
   OnPropertyChanged(this,new PropertyChangedEventArgs("Error"));
}

答案 1 :(得分:0)

现在,我在我的模型上添加了这个方法。

    public Boolean IsModelValid()
    {
        Boolean isValid = true;
        PropertyInfo[] properties = GetType().GetProperties(BindingFlags.Public | BindingFlags.Instance);

        foreach (PropertyInfo p in properties)
        {
            if (!p.CanWrite || !p.CanRead)
            {
                continue;
            }
            if (this[p.Name] != null)
            {
                isValid = false;
            }
        }
        return isValid;
    }

我将对象本身绑定在PropertyChanged事件上,

    public MyClassName()
    {
        PropertyChanged += CheckModelValidity;
        CheckModelValidity(null, null);
    }

当它改变时,我调用这个方法,如果结果与我的实际公共成员不同,我会更新它:

    private void CheckModelValidity(object sender, PropertyChangedEventArgs e)
    {
        bool isModelValid = IsModelValid();
        if(isModelValid!= IsValid)
        {
            IsValid = isModelValid;
        }
    }

然后我可以绑定IsValid属性。

我不知道是否有更好的解决方案?

答案 2 :(得分:0)

感谢 Bob Vale 的想法! 我注意到我有几个模型并且代码非常重复。我创建了这个基类:

using System;
using System.ComponentModel;
using System.ComponentModel.DataAnnotations.Schema;
using System.Text;

namespace Core.Models
{
    public abstract class ValidatableObject : IDataErrorInfo
    {
        public virtual bool IsValid() => this[null] == null;

        [NotMapped]
        public string? Error => this[null];

        [NotMapped]
        protected abstract (string, Func<string?>)[] Checks { get; }

        public virtual string? this[string? name] => validate(name, Checks);

        private static string? validate(string? name, params (string, Func<string?>)[] checks)
        {
            StringBuilder results = new();

            foreach ((string val, Func<string?> check) in checks)
            {
                if (String.IsNullOrEmpty(name) || name == val)
                {
                    string? result = check();
                    if (result != null)
                        results.AppendLine(result);
                }
            }

            return results.Length == 0
                ? null
                : results.ToString(0, results.Length - Environment.NewLine.Length);
        }
    }
}

这里的用法:

    private class Validatable : ValidatableObject
    {
        public string Email { get; set; }
        public string Comment { get; set; }

        protected override (string, Func<string?>)[] Checks => new (string, Func<string?>)[]
        {
            (nameof(Email), () => Validate.Email(Email)),
            (nameof(Comment), () => Validate.LengthOfOptionalString(Comment)),
        };
    }
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