我有3个编辑文本字段。这三个人都使用了文本观察器。它运作良好。这意味着，如果我在edittext A中输入内容，它会在edittext B和edittext C中提供基于A.的结果。我想得到合并结果。我想像这样过滤结果：
如果我在国家号码中键入“2”并在注册号码中键入“3”，结果应该是这样的
234 34 john
2890 345 xxxx
21 3 smith
我将过滤后的值保存在arraylist中并将该arraylist传递给适配器。
edtNationalityInfo.addTextChangedListener(new TextWatcher() {
public void afterTextChanged(Editable s) {
}
public void beforeTextChanged(CharSequence s, int start, int count,
int after) {
}
public void onTextChanged(CharSequence s, int start, int before,
int count) {
textlength = edtNationalityInfo.getText().length();
if (textlength > 0)
nationalFlag = true;
else
nationalFlag = false;
// filtered_data.clear();
for (int i = 0; i < data.size(); i++) {
if (textlength <= data.get(i).get_nationalityno().length()) {
if (edtNationalityInfo
.getText()
.toString()
.equalsIgnoreCase(
(String) data.get(i)
.get_nationalityno()
.subSequence(0, textlength))) {
filtered_data.add(data.get(i));
}
}
}
lvVotersList.setAdapter(new TextWatcherAdapter(Attendance.this,
filtered_data));
}
});
edtVoterName.addTextChangedListener(new TextWatcher() {
public void afterTextChanged(Editable s) {
}
public void beforeTextChanged(CharSequence s, int start, int count,
int after) {
}
public void onTextChanged(CharSequence s, int start, int before,
int count) {
textlength = edtVoterName.getText().length();
if (textlength > 0)
nameFlag = true;
else
nameFlag = false;
// filtered_data.clear();
for (int i = 0; i < data.size(); i++) {
if (textlength <= data.get(i).get_name().length()) {
if (edtVoterName
.getText()
.toString()
.equalsIgnoreCase(
(String) data.get(i).get_name()
.subSequence(0, textlength))) {
filtered_data.add(data.get(i));
}
}
}
lvVotersList.setAdapter(new TextWatcherAdapter(Attendance.this,
filtered_data));
}
});
这是我的ArrayList：
data = new ArrayList<DataAttendance>();
filtered_data = new ArrayList<DataAttendance>();
//我的数据模型类：
public class DataAttendance {
public String _id = null;
public String _serialno = null;
public String _nationalityno = null;
public String _voteCasted = null;
public String _voteCastedTime = null;
public String _name = null;
public DataAttendance() {
}
public DataAttendance(String _name, String _serialno,
String _nationalityno, String _voteCasted, String _voteCastedTime) {
this._name = _name;
this._nationalityno = _nationalityno;
this._serialno = _serialno;
this._voteCasted = _voteCasted;
this._voteCastedTime = _voteCastedTime;
}
public String get_id() {
return _id;
}
public void set_id(String _id) {
this._id = _id;
}
public String get_name() {
return _name;
}
public void set_name(String _name) {
this._name = _name;
}
public String get_nationalityno() {
return _nationalityno;
}
public void set_nationalityno(String _nationalityno) {
this._nationalityno = _nationalityno;
}
public String get_serialno() {
return _serialno;
}
public void set_serialno(String _serialno) {
this._serialno = _serialno;
}
public String get_voteCasted() {
return _voteCasted;
}
public void set_voteCasted(String _voteCasted) {
this._voteCasted = _voteCasted;
}
public String get_voteCastedTime() {
return _voteCastedTime;
}
public void set_voteCastedTime(String _voteCastedTime) {
this._voteCastedTime = _voteCastedTime;
}
现在我变得像：
如果我在国家号码中键入“2”并在注册号码中键入“3”，结果应该是这样的
234 434 siva
2890 345 elma
21 23 laura
希望我能在这里得到帮助..！
// --------------------------------------------- ---------------------------------------
我有另一个数组列表的解决方案：
这是：
它可能对某人有帮助..
edtVoterName.addTextChangedListener(new TextWatcher() {
public void afterTextChanged(Editable s) {
}
public void beforeTextChanged(CharSequence s, int start, int count,
int after) {
}
public void onTextChanged(CharSequence s, int start, int before,
int count) {
int Votertextlength = edtVoterName.getText().length();
if (Votertextlength > 0) {
nameFlag = true;
} else {
nameFlag = false;
}
textlength = edtVoterName.getText().length();
if (nationalFlag == true || registerFlag == true) {
Log.d("Attendance Flag : ",
" The Attendance nationalFlag == " + nationalFlag
+ " registerFlag == : " + registerFlag);
ArrayList<DataAttendance> temp_data;
temp_data = new ArrayList<DataAttendance>();
textlength = edtVoterName.getText().length();
// filtered_data.clear();
for (int i = 0; i < filtered_data.size(); i++) {
if (textlength <= filtered_data.get(i).get_name()
.length()) {
if (edtVoterName
.getText()
.toString()
.equalsIgnoreCase(
(String) filtered_data.get(i)
.get_name()
.subSequence(0, textlength))) {
temp_data.add(filtered_data.get(i));
}
}
}
filtered_data = temp_data;
lvVotersList.setAdapter(new TextWatcherAdapter(
Attendance.this, filtered_data));
} else {
filtered_data.clear();
for (int i = 0; i < data.size(); i++) {
if (textlength <= data.get(i).get_name()
.length()) {
if (edtVoterName
.getText()
.toString()
.equalsIgnoreCase(
(String) data.get(i)
.get_name()
.subSequence(0, textlength))) {
filtered_data.add(data.get(i));
}
}
}
lvVotersList.setAdapter(new TextWatcherAdapter(
Attendance.this, filtered_data));
}
}
});
答案 0 :(得分：0)
使用此
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
EditText e = new findViewById(R.id.editText);
EditText e1 = new findViewById(R.id.editText1);
EditText e2 = new findViewById(R.id.editText2);
e.addTextChangedListener(new CustomTextWatcher(e));
e.addTextChangedListener(new CustomTextWatcher(e1));
e.addTextChangedListener(new CustomTextWatcher(e2));
}
private class CustomTextWatcher implements TextWatcher {
private EditText mEditText;
public CustomTextWatcher(EditText e) {
mEditText = e;
}
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
public void onTextChanged(CharSequence s, int start, int before, int count) {
if(mEditText.getId()== R.id.editText){}
else if(mEditText.getId()== R.id.editText2){}
else{}
}
public void afterTextChanged(Editable s) {
}
}