java.util.InputMismatchException

时间:2012-12-01 03:38:04

标签: java sockets client-server

编辑:输入为25565,127.0.0.1,25565,testpassword,stop

我写了一些简单的代码来通过RCON向服务器发送命令,我收到了这个错误:

Exception in thread "main" java.util.InputMismatchException
at java.util.Scanner.throwFor(Unknown Source)
at java.util.Scanner.next(Unknown Source)
at java.util.Scanner.nextInt(Unknown Source)
at java.util.Scanner.nextInt(Unknown Source)
at mainclass.main(mainclass.java:21)

这是我的代码:

import net.sourceforge.rconed.*;
import net.sourceforge.rconed.exception.BadRcon;
import net.sourceforge.rconed.exception.ResponseEmpty;

import java.net.SocketTimeoutException;
import java.util.Scanner;
class mainclass {
    public static void main(String args[]) throws SocketTimeoutException, BadRcon, ResponseEmpty{
        Scanner input = new Scanner(System.in);

        String ipStr, password, command;
        int localPort, port;

        System.out.println("Enter local Query port: ");
        localPort = input.nextInt();

        System.out.println("Enter game IP: ");
        ipStr = input.nextLine();

        System.out.println("Enter game port: ");
        port = input.nextInt();

        System.out.println("Enter password: ");
        password = input.nextLine();

        System.out.println("Enter command: ");
        command = input.nextLine();

        Rcon.send(localPort, ipStr, port, password, command);
    }
}

注意:Rcon.send函数分别需要int,string,int,string和string。

2 个答案:

答案 0 :(得分:2)

请注意,Scanner#nextInt(),Scanner#nextDouble()和类似方法不处理行尾(EOL)令牌,因此如果您使用这些方法之一并希望使用调用nextLine()得到另一行,你必须自己处理第一个EOL。尝试更改

    Scanner input = new Scanner(System.in);

    String ipStr, password, command;
    int localPort, port;

    System.out.println("Enter local Query port: ");
    localPort = input.nextInt();

    System.out.println("Enter game IP: ");
    ipStr = input.nextLine();

    System.out.println("Enter game port: ");
    port = input.nextInt();

    System.out.println("Enter password: ");
    password = input.nextLine();

    System.out.println("Enter command: ");
    command = input.nextLine();

    Rcon.send(localPort, ipStr, port, password, command);

到:

    Scanner input = new Scanner(System.in);

    String ipStr, password, command;
    int localPort, port;

    System.out.println("Enter local Query port: ");
    localPort = input.nextInt();
    input.nextLine();  // ***** added! *****

    System.out.println("Enter game IP: ");
    ipStr = input.nextLine();

    System.out.println("Enter game port: ");
    port = input.nextInt();
    input.nextLine();  // ***** added! *****

    System.out.println("Enter password: ");
    password = input.nextLine();

    System.out.println("Enter command: ");
    command = input.nextLine();

    Rcon.send(localPort, ipStr, port, password, command);

答案 1 :(得分:0)

你可以试试这个。注意我在所有场景中使用了input.nextLine()。

    System.out.println("Enter local Query port: ");
    localPort = Integer.parseInt(input.nextLine());

    System.out.println("Enter game IP: ");
    ipStr = input.nextLine();

    System.out.println("Enter game port: ");
    port = Integer.parseInt(input.nextLine());

    System.out.println("Enter password: ");
    password = input.nextLine();

    System.out.println("Enter command: ");
    command = input.nextLine();