使用PHP字符串+结果返回未知的等号?

时间:2012-12-04 10:20:10

标签: php string strpos

我有一个名为$message的字符串变量,如下所示:

        * Time Stamp: 2012-12-03 16:36:04 
        * Speed: 7 km/h 
        * Heading: 356 deg (N) 
        * Event ID: -48 
        * Event Desc: .Arrived at Inbound Receiving 
        * Event Value: -56
        * Event Value Type: 0

然后我尝试使用以下代码从变量中提取事件和时间戳值:

$event = null;
$lines = explode(PHP_EOL, $message);
foreach($lines as $line) {
  // skip empty lines
  if(strlen($line) == 0) {
    continue;
  }
  $tokens = explode(':', $line);
  // tokens[0] contains the key , e.g. Event Value
  // tokens[1]~[N] contains the value (where N is the number of pieces), e.g. -56
  // stitch token 1 ~ N
  $key = $tokens[0]; 
  unset($tokens[0]);
  $val = implode(': ', $tokens);
  // do your extra logic here, e.g. set $event variable to value
  if(strpos($key, 'Event Desc') > -1) {
    $event = $val;
  }
   if(strpos($key, 'Time Stamp') > -1) {
   $time = $val;
  }
}

这很有效,唯一的问题是返回的值是:

.Arrived at Arrived at Inbound Receiving =

2012-12-03 16:36:04  =

等号来自何处以及如何将其与尾随空格一起删除?

我的预期结果是:

.Arrived at Arrived at Inbound Receiving

2012-12-03 16:36:04

这是它在字符串变量中的显示方式。 一如既往地谢谢。

4 个答案:

答案 0 :(得分:2)

你可以尝试

preg_match_all("/ ([a-z ]+):([a-z0-9:\-. ]+)/i", $string,$match);
$values = array_combine($match[1], $match[2]) ;

echo $values['Time Stamp'] ,PHP_EOL ;
echo $values['Speed'] ,PHP_EOL ;
echo $values['Heading'] ,PHP_EOL ;
echo $values['Event Desc'] ,PHP_EOL ;
// .... etc

输出

 2012-12-03 16:36:04 
 7 km
 356 deg 
 .Arrived at Inbound Receiving  

Online Demo

答案 1 :(得分:1)

这将为您提供正确的密钥和价值。

list($key, $value) = explode(':', $line, 2);
$key = trim($key);
$value = trim(quoted_printable_decode($value));

答案 2 :(得分:1)

我的猜测是你从电子邮件中收到了$message个内容。如果是这种情况,请先尝试通过quoted_printable_decode运行内容。

答案 3 :(得分:0)

如果您使用

echo $time;
echo $event;

它将显示2012-12-03 16:36:04。仅限入站接收