Question

我已经尝试了将查询存储为变量并使用fetch_array的所有内容，但是当我尝试打印$ _SESSION ['permission']时，它只是给我输出“Array”。我不知道该怎么办请帮助。

<?php
session_start(); 
mysql_connect("localhost","",""); 
mysql_select_db("a"); 
if(isset($_SESSION['loggedin']))
{
    header("Location: http://www.mywebsite.com/whatever");
} 
if($_POST['submit'])
{
   $name = mysql_real_escape_string($_POST['username']); 
   $pass = mysql_real_escape_string($_POST['password']); 
   $mysql = mysql_query("SELECT * FROM users WHERE name = '{$name}' AND password = '{$pass}'"); 
   $result = mysql_query("SELECT permission FROM users WHERE name = '{$name}' AND password = '{$pass}'");
   $permission = mysql_fetch_array($result);
   if(mysql_num_rows($mysql) < 1)
   {
     die("Password was incorrect!");
   } 
   $_SESSION['loggedin'] = "YES"; 
   $_SESSION['name'] = $name; 
   $_SESSION['permission'] = $permission;

   header ("Location: http://www.mywebsite.com/whatever"); 
}  
echo "<form type='login.php' method='POST'>
Username: <br>
<input type='text' name='username'><br>
Password: <br>
<input type='password' name='password'><br>
<input type='submit' name='submit' value='Login'>
</form>"; 
?>

Answer 1

您需要使用循环遍历结果集

while($row = mysql_fetch_array($result)) {
//use each row value($row) as per your need
}

所以，我相信，你想要实现这样的目标，

if(isset($_POST['submit']))
{
$name = mysql_real_escape_string($_POST['username']); 
$pass = mysql_real_escape_string($_POST['password']); 
$result = mysql_query("SELECT permission FROM users WHERE name = '{$name}' AND password                                 = {$pass}'"); 
$permission = mysql_fetch_array($result);
$mysql = mysql_query("SELECT * FROM users WHERE name = '{$name}' AND password =     '{$pass}'"); 
if(mysql_num_rows($mysql) < 1)
{    
 die("Password was incorrect!");
} 

$_SESSION['loggedin'] = "YES"; 
$_SESSION['name'] = $name; 
$i = 0;
while($row = mysql_fetch_array($result)) {    
$_SESSION['permission' . $i] = $row;
$i++;
}
  header ("Location: "); 
 }

Answer 2

如果$row是查询的结果，则需要指定$_SESSION['permission'] = $row[column_name];

这样的列

Answer 3

刚编辑了代码的POST部分。请记住，您必须获取结果并使用关联数组来获取特定列的值：

if($_POST['submit'])
{
   $name = mysql_real_escape_string($_POST['username']); 
   $pass = mysql_real_escape_string($_POST['password']); 
   $result = mysql_query("SELECT * FROM users WHERE name = '{$name}' AND password = {$pass}'");

   if(!$row = mysql_fetch_array($result))
   {
      die("Password was incorrect!");
   }

   $_SESSION['loggedin'] = "YES"; 
   $_SESSION['name'] = $name; 
   $_SESSION['permission'] = $row['permission'];
   header ("Location: "); 
}

无需再运行两次查询。

Answer 4

您正在将行数组分配给$_SESSION['permission']变量，因此当您打印它时会得到数组。尝试在该阵列上使用print_r，您将看到其中的内容。示例：print_r($_SESSION['permission']); Print无法打印数组。使用print_r或var_dump了解当您再次发现这种情况时会发生什么。

尝试从SQL查询的结果中存储会话变量

4 个答案: