Question

我有2张桌子第1张桌子包含姓名，电子邮件，vegetable_Fruits和饮料

CREATE TABLE Likes
(
Name varchar(20),
email varchar(20),
Vegetables_Fruits varchar(20),
Drinks varchar(20)
)

我正在存储蔬菜，水果和饮料等人的姓名和电子邮件一个人可以拥有任何一个价值如果一个人喜欢蔬菜我将更新表格

name email 1 0

如果一个人喜欢水果，那么

name email 2 0

如果一个人喜欢饮料，那么

name email 0 1

插入查询

INSERT INTO Likes(Name,email,Vegetables_Fruits,Drinks)
     VALUES("aaa","aaa@example.com",1,0),("bbb","bbb@example.com",2,0),("ccc","cc@example.com",0,1),("ddd","dd@example.com",2,0),("eee","ee@example.com",2,0),("fff","ff@example.com",1,0),("ggg","gg@example.com",0,1),("hhh","hh@example.com",0,1)

我有另一张包含电子邮件列表的表

CREATE TABLE emailList
(
Likes_Vegetables varchar(50),
Likes_Fruits varchar(50),
Drinks varchar(50)
)

插入查询

INSERT INTO emailList(Likes_Vegetables,Likes_Fruits,Drinks)
       VALUES("aaa@example.com,ff@example.com","bbb@example.com,dd@example.com,'ee@example.com'","hh@example.com,gg@example.com,cc@example.com")

我想根据1st table（Likes）的值更新第二个表（emailList）这个

的查询是什么

Answer 1

update emailList 
set 
Likes_vegetables=(select Group_concat(email) from LIKES where Vegetables_Fruits=1),
Likes_Fruits=(select Group_concat(email) from LIKES where Vegetables_Fruits=2),
Drinks=(select Group_concat(email) from LIKES where Drinks=1)

Answer 2

我认为您正在搜索group_concat，也许这样查询

INSERT INTO emailList(Likes_Vegetables,Likes_Fruits,Drinks)
      values ( (SELECT GROUP_CONCAT(email) FROM Likes WHERE Vegetables_Fruits=1) , (SELECT GROUP_CONCAT(email) FROM Likes WHERE Vegetables_Fruits=2) , (SELECT GROUP_CONCAT(email) FROM Likes WHERE Vegetables_Fruits=0) )

Answer 3

这可以解决你的问题 -

更新emailList设置Likes_Vegetables = 的concat（Likes_Vegetables “aaa@example.com”）， Likes_Fruits = concat（Likes_Fruits，“ee@example.com”）， Drinks = concat（Drinks，“cc @ example.com”）;

如何更新包含逗号分隔值的表行？

3 个答案: