Question

我需要通过扫描最强的可用Wifi来启动活动，从而在建筑物中找到我当前的位置。我想在那栋楼里只找到3个地方。因此，如果我目前靠近这些位置，我会点击一个按钮扫描最强的可用Wifi以启动活动。

我需要在建筑物中扫描可用的Wifi。
获得3个最强信号。
然后检测这3个最强信号的SSID中是否有任何一个与我想要找到的特定SSID相同。
如果我的SSID是最强的3个信号之一，那么应用程序将启动xml布局活动，

到目前为止，我已经有编码来扫描最强大的Wifi。但是，当检测到最强的特定Wifi SSID时，我不知道如何启动活动。我不需要有关Wifi的信息，只需启动包含我信息的活动布局。

目前我正在使用以下代码来扫描我从here获得的最强Wifi信号：

WiFiDemo.java

public class WiFiDemo extends Activity implements OnClickListener {
private static final String TAG = "WiFiDemo";
WifiManager wifi;
BroadcastReceiver receiver;

TextView textStatus;
Button buttonScan;

/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    // Setup UI
    textStatus = (TextView) findViewById(R.id.textStatus);
    buttonScan = (Button) findViewById(R.id.buttonScan);
    buttonScan.setOnClickListener(this);

    // Setup WiFi
    wifi = (WifiManager) getSystemService(Context.WIFI_SERVICE);

    // Get WiFi status
    WifiInfo info = wifi.getConnectionInfo();
    textStatus.append("\n\nWiFi Status: " + info.toString());

    // List available networks
    List<WifiConfiguration> configs = wifi.getConfiguredNetworks();
    for (WifiConfiguration config : configs) {
        textStatus.append("\n\n" + config.toString());
    }

    // Register Broadcast Receiver
    if (receiver == null)
        receiver = new WiFiScanReceiver(this);

    registerReceiver(receiver, new IntentFilter(
            WifiManager.SCAN_RESULTS_AVAILABLE_ACTION));
    Log.d(TAG, "onCreate()");
}

@Override
public void onStop() {
    unregisterReceiver(receiver);
}

public void onClick(View view) {
    Toast.makeText(this, "On Click Clicked. Toast to that!!!",
            Toast.LENGTH_LONG).show();

    if (view.getId() == R.id.buttonScan) {
        Log.d(TAG, "onClick() wifi.startScan()");
        wifi.startScan();
    }
} }

WiFiScanReceiver.java

      public class WiFiScanReceiver extends BroadcastReceiver {
        private static final String TAG = "WiFiScanReceiver";
        WiFiDemo wifiDemo;

      public WiFiScanReceiver(WiFiDemo wifiDemo) {
        super();
        this.wifiDemo = wifiDemo;
      }

      @Override
      public void onReceive(Context c, Intent intent) {
        List<ScanResult> results = wifiDemo.wifi.getScanResults();
        ScanResult bestSignal = null;
        for (ScanResult result : results) {
          if (bestSignal == null
              || WifiManager.compareSignalLevel(bestSignal.level, result.level) < 0)
            bestSignal = result;
        }

        String message = String.format("%s networks found. %s is the strongest.",
            results.size(), bestSignal.SSID);
        Toast.makeText(wifiDemo, message, Toast.LENGTH_LONG).show();

        Log.d(TAG, "onReceive() message: " + message);
      }

    }

Answer 1

您只需要从onReceive开始您的活动。除非我不理解你的问题，否则你只需要解雇你的活动。由于你的接收器上有上下文onReceive，你只需要startActivity（）

Start Activity inside onReceive BroadcastReceiver

 @Override
    public void onReceive(Context context, Intent intent) {
        //start activity
        Intent i = new Intent();
        i.setClassName("com.test", "com.test.MainActivity");
        i.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
        context.startActivity(i);
    }

不要忘记在清单中为它定义适当的过滤器。 http://developer.android.com/reference/android/content/BroadcastReceiver.html

扫描可用的wifi，检测特定的最强Wifi SSID以启动XML活动布局

1 个答案: