尝试从Tridion 2011 SP1下载多媒体图像时不支持获取文件路径

时间:2012-12-19 11:42:56

标签: tridion tridion-2011

我收到“不支持给定路径的格式。”当我只是尝试从我的SDL Tridion 2011 SP1下载多媒体图像时,下面是我得到的路径,不知道“N:”等即将到来。

  

D:\ delete \ Images \ N:\ dmc.FlipMedia.Clients.TestCMS \ 2009_WorkInProgress \ creatives \ 05_May \ 16岁以下儿童免费访问英国\ assets_graphics \ jpg \ Kids_go_free_385x306.jpg

以下是代码:

 public static void GetBinaryFromMultimediaComponent(string tcm, CoreServiceClient client, StreamDownloadServiceClient streamDownloadClient)
        {           

            ComponentData multimediaComponent = client.ReadItem(tcm) as ComponentData;

            // Generate you own file name, and file location
            string file = "D:\\delete\\Images\\" + multimediaComponent.BinaryContent.Filename;//Here I am getting above path

            // Write out the existing file from Tridion
            FileStream fs = File.Create(file);//Here getting the exception
            byte[] binaryContent = null;

            if (multimediaComponent.BinaryContent.FileSize != -1)
            {
                Stream tempStream = streamDownloadClient.DownloadBinaryContent(tcm);
                var memoryStream = new MemoryStream();
                tempStream.CopyTo(memoryStream);
                binaryContent = memoryStream.ToArray();
            }

            fs.Write(binaryContent, 0, binaryContent.Length);
            fs.Close();
        } 

请建议!!

修改:

我使用Nuno建议获得文件名,但是前进到

 Stream tempStream = streamDownloadClient.DownloadBinaryContent(tcm);

我收到以下错误,对此有何建议?

The content type multipart/related; type="application/xop+xml";start="";boundary="uuid:5f66d04b-76d3-4d3a-b8e3-b7b91e00ed32+id=2";start-info="text/xml" of the response message does not match the content type of the binding (text/xml; charset=utf-8). If using a custom encoder, be sure that the IsContentTypeSupported method is implemented properly. The first 595 bytes of the response were: ' --uuid:5f66d04b-76d3-4d3a-b8e3-b7b91e00ed32+id=2 Content-ID: Content-Transfer-Encoding: 8bit Content-Type: application/xop+xml;charset=utf-8;type="text/xml" '.

2 个答案:

答案 0 :(得分:5)

正如您现在可能已经想到的那样,string file = "D:\\delete\\Images\\" + multimediaComponent.BinaryContent.Filename;会附加完整的文件名(包括路径),因此会生成错误的路径。

尝试使用string file = "D:\\delete\\Images\\" + Path.GetFilename(multimediaComponent.BinaryContent.Filename);

之类的内容

答案 1 :(得分:0)

这样做: -

Stream tempStream = streamDownloadClient.DownloadBinaryContent(tcmId);
MemoryStream memoryStream = new MemoryStream();
int b;
do
{
    b = tempStream.ReadByte();
    memoryStream.WriteByte((byte)b);
} while (b != -1);

binaryContent = memoryStream.ToArray();​