Question

我几乎无处不在地发现这一点。我有以下SQL语句：

SELECT COUNT(*) FROM `job_sheet`
LEFT JOIN deliveries ON job_sheet.job_id=deliveries.jID
WHERE job_sheet.completion=".ORDER_COMPLETE."
AND deliveries.ship_date>job_sheet.delivery_date

这基本上告诉我哪些已完成的作业已经过delivery_date（DUE DATE）。但是，真正的交付日期实际上是7 business 天（假期并不重要。基本上只是跳过周末），而不是数据库中的内容。

我需要做的是在此部分添加7天：deliveries.ship_date>job_sheet.delivery_date + 7 business days

我的第一个想法是使用DATEADD（）函数，但我很少使用它，并且在这种情况下如何实现它会非常混乱。

日期存储为：YYYY-MM-DD

Answer 1

试试这个

   SELECT COUNT(*) FROM `job_sheet`
   LEFT JOIN deliveries ON job_sheet.job_id=deliveries.jID
   WHERE job_sheet.completion=".ORDER_COMPLETE."
   AND  deliveries.ship_date> DATE_ADD(`job_deliveries.ship_date` , INTERVAL 7 DAY)

REFRENCE OF ADD_DATE

Answer 2

这应该有用，虽然我还没有测试过，因为我没有;要安装一个mysql实例来检查：

SELECT COUNT(*) FROM `job_sheet`
LEFT JOIN deliveries ON job_sheet.job_id=deliveries.jID
WHERE job_sheet.completion=".ORDER_COMPLETE."
AND deliveries.ship_date>DATE_ADD(job_sheet.delivery_date,INTERVAL 7 DAY)

Answer 3

好吧，在我到达这里的帮助下，添加7天约会很容易。由于我特别需要在特定日期添加7个工作日，因此我不得不使用一些PHP以及我的其余脚本。我使用自定义DateHelper类来完成这项工作。

class DateHelper {

    var $holidays = array("2010-07-04", "2010-09-06", "2010-09-23", "2010-10-11", "2010-11-01", "2010-11-11",  "2010-11-25", "2010-12-25");
    const oneday = 86400; 
    const weekend = 172800; 

    function addBusinessDays($start_date, $business_days)
    {

        if (date('N', $start_date) == 6)
        { // If start date is on Saturday
            $new_start_date = $start_date + self::weekend;
        } 
        elseif (date('N', $start_date) == 7)
        { // If start date is on Sunday
            $new_start_date = $start_date + self::oneday;
        } 
        else 
        {
            $new_start_date = $start_date;
        }

        $due_date = $new_start_date + $business_days * self::oneday;
        $due_date += floor($business_days / 5) * self::weekend;

        if (($business_days % 5) + date('N', $new_start_date) >= 6)
        {
            $due_date += self::weekend; // Add 2 days to compensate for the weekend
        }

        foreach($this->holidays as $holiday)
        {
            $time_stamp = strtotime($holiday);

            // If the holiday falls between the start date and end date
            // and is on a weekday
            // Or if $new_start_date is on a holiday
            if (($start_date <= $time_stamp && $time_stamp <= $due_date && date("N", $time_stamp) < 6) || date("Y-m-d", $new_start_date) == $holiday)
            {
                $due_date += self::oneday;
                if (date('N', $due_date) >= 6)
                {
                    // If due date on Saturday or Sunday
                    $due_date += self::weekend;
                }
            }
        }

        return $due_date;
    }
}

我将这个课程结合到了这个：

//jobs that were shipped past their due date
public function totalShippedLate($offset = 7)
{
    $sql = mysql_query("SELECT deliveries.ship_date, job_sheet.delivery_date, deliveries.qty_shipped FROM `job_sheet` LEFT JOIN deliveries ON job_sheet.job_id=deliveries.jID WHERE job_sheet.completion=".jobInfo::ORDER_COMPLETE."") or die(mysql_error());
    $x = 0; // number of items shipped
    while($data = mysql_fetch_array($sql))
    {
        $date = new DateHelper();
        $offset_date = date("Y-m-d", $date->addBusinessDays(strtotime($data['delivery_date']), $offset));
        if($data['ship_date']>$offset_date)
        {
            $x += $data['qty_shipped']; 
        }
    }
    return $x;  
}

这将返回超过截止日期的货品数量，并带有可自定义的偏移量

为SQL查询添加工作日

3 个答案: