Question

我的SQL查询有问题

我有

T1：

ID    STATUS   REPORTEDBY  
1     CLOSED   USER1
2     CLOSED   USER2
3     NEW      USER1
4     INPRG    USER1
5     CLOSED   USER1

T2：

T1ID  STATUS
1     NEW
1     CHECKING
1     CLOSED

2     NEW
2     CHECKING
2     CLOSED


3     NEW

4     CHECKING
4     INPRG 

5     INPRG
5     CLOSED

结果我想得到这个：

USER    NumberHasCHECKING  NumberDifferentFromNewChecking  NumberClosed

USER1          2                         3                      2
USER2          1                         1                      1

我想通过REPORTEDBY字段获取结果组

来自T1的记录数量，在T2中存在CHECKING状态，
来自T1的记录数目，其状态与NEW或T1中的CHECKING不同
和T1中当前处于CLOSED状态的记录数。

select reportedby,count (case when T2.status='CHECKING' then 1 end) as NumberHasChecking,
count (case when T2.status not in ('NEW','CHECKING') then 1 end) as NumberDifferentFromNewChecking, 
count (case when T1.status='CLOSED' then 1 end) as  NumberClosed
from t1
inner join t2 on T1.ID=T2.T1ID
group by reportedby

但是在我进行内部联接后，我在第二和第三列获得了更大的结果。怎么解决这个？谢谢

Answer 1

不确定这是否适用于DB2：

Select 
  ReportedBy,
  Count (Case When t2.Status = 'CHECKING' Then 1 End) As NumberHasChecking,
  Count (Distinct Case When t1.Status Not In ('NEW','CHECKING') Then t1.Id End) As NumberDifferentFromNewChecking, 
  Count (Distinct Case When t1.Status = 'CLOSED' Then t1.Id End) As NumberClosed
From
  t1
    Inner Join
  t2
    on t1.Id = t2.t1Id
Group By 
  ReportedBy

Answer 2

试试这个：

select 
    reportedby,
    sum (T2.CheckingState) as NumberHasChecking, 
    count (case when T1.status not in ('NEW','CHECKING') then 1 end) as NumberDifferentFromNewChecking, 
    count (case when T1.status='CLOSED' then 1 end) as NumberClosed 
from
    T1 inner join 
    (
        SELECT 
            T1ID,
            COUNT(CASE WHEN STATUS='NEW'      THEN 1 END) NewState,
            COUNT(CASE WHEN STATUS='CHECKING' THEN 1 END) CheckingState,
            COUNT(CASE WHEN STATUS='CLOSED'   THEN 1 END) ClosedState
        FROM T2
        GROUP BY T1ID
    ) T2 ON T1.ID=T2.T1ID 
group by reportedby

JOINING更多表时SQL SQL“COUNT”错误

2 个答案: