Question

再一次努力，可以提供一些帮助它可能看起来很有用，但不是，:)）

我有一组渴望加载和关系的数组。这是代码（Laravel）

$user = User::with(array('profile','classrooms','warnings','observation','complaint','pmainduction','workshops','grievances','grievances.grievanceaction'))
    ->where('id', '=', $id)->get();

这可以在每个员工的个人资料页面中完美地获取数据。当我遍历申诉和每个申诉的申诉时，它会复制数据并且不会像在print_r中那样显示

数组的一部分是

你可以看到我有怨言对象1＆amp; 2他们每个人都有自己的不满。在我的输出中，我想实现这个

--------------------------------------------------------------
|  Grievance name: 1  |   Date:     |   Action:    |  Status: |
--------------------------------------------------------------
|   (grievanceaction data for 1st grievance in loop )        |
|   action: relationship action here      date: with date    |
|                                                            |
--------------------------------------------------------------
--------------------------------------------------------------
|  Grievance name: 2  |   Date:     |   Action:    |  Status: |
--------------------------------------------------------------
|   (grievanceaction data for 2nd grievance in loop )        |
|   action: relationship action here      date: with date    |
|                                                            |
--------------------------------------------------------------

我目前有

--------------------------------------------------------------
|  Grievance name: 1  |   Date:     |   Action:    |  Status: |
--------------------------------------------------------------
|   (grievanceaction data for 1st grievance in loop )         |
|                                                             |
|                                                             |
--------------------------------------------------------------
--------------------------------------------------------------
|  Grievance name: 2  |   Date:     |   Action:    |  Status: |
--------------------------------------------------------------
|   (grievanceaction data for 1st grievance in loop )         |
|                                                             |
|                                                             |
--------------------------------------------------------------

代码是

<table width="100%" class="table table-striped table-bordered">

@if(empty($user['0']->grievances))
   <thead>
   <tr>
   <th colspan="3">  No Grievances logged.</th>
   </tr>
   </thead>
@else
   <thead>

@foreach ($user['0']->grievances as $grievance )

<tr>
<th>Date: {{ date("d-M-Y",strtotime($grievance->date)) }}</th>
<th>Nature: {{ $grievance->nature }}</th>
<th>Initial Action:</strong> {{ $grievance->action }}  </th>
<th>Status: 

    @if ( $grievance->status == 1 )
          Active
    @else
          Resolved
    @endif
</th>
</tr>
</thead>
<tbody>
<tr>
<td colspan="4">Description: {{ $grievance->details }} </td>
</tr>
<tr>
<td colspan="4">

              <!-- here is where i try and loop through the grievanceactions -->

              <table width="100%" class="table table-striped table-bordered">
              <tr>
              <th scope="col">Date</th>
              <th scope="col">Action</th>
              </tr>
              <tbody>
              @foreach ($user['0']->grievances['0']->grievanceaction as $grievance )
              <tr>
              <td>{{ date("D, d-M-Y H:i",strtotime($grievance->created_at)) }}</td>
              <td>{{ $grievance->action }}</td>
              </tr>
              @endforeach
              </tbody>
              </table>
</td>
</tr>
@endforeach

@endif
</td>
</tr>
</tbody>
</table>

我真的很感激一些帮助，谢谢

：）

Answer 1

问题是你硬编码，你总是采取$user['0']->grievances['0']的冤情，例如第一个。申诉循环应该是：

              @foreach ($grievance->grievanceaction as $grievanceaction )
              <tr>
              <td>{{ date("D, d-M-Y H:i",strtotime($grievanceaction->created_at)) }}</td>
              <td>{{ $grievanceaction->action }}</td>
              </tr>
              @endforeach

编辑：一些注释：

Blade中有一个@forelse循环，其中@empty部分为get()，这样可以在顶部保存if。
您不需要为用户使用first()，您只需使用{{1}}，因此每次都不需要['0']。
通常的做法是将* -many关系复数命名为复数，以表示它是一系列结果（grievanceaction - ＆gt; grievanceactions）。

laravel循环通过急切加载的嵌套关系

1 个答案: