Question

我正在编写一个包含多个LEFT JOIN的复杂MySQL查询，以组合来自多个不同表的数据。

$public_query = 
"SELECT * FROM  `wsat_ib` 
LEFT JOIN wp_usermeta ON wsat_ib.user_id = wp_usermeta.user_id
LEFT JOIN wpjb_resume ON wsat_ib.user_id = wpjb_resume.user_id
LEFT JOIN wpjb_field_value ON wpjb_resume.id=wpjb_field_value.job_id 
LEFT JOIN wpjb_application ON wpjb_application.user_id = wsat_ib.user_id
WHERE wp_usermeta.meta_key =  'target_employer'
AND wp_usermeta.meta_value =  'public'
AND wpjb_resume.is_active =1
";

我的问题：表wp_usermeta可以为同一个user_id提供多行。例如，用户（具有user_id = 5）可能在表wp_usermeta中具有多于一行，其字段为：meta_key，即“target_employer”。如果不清楚，行可能看起来像这样。

id    user_id    meta_key           meta_value
1     5          target_employer    13
2     5          target_employer    53
3     79         target_employer    21

我的问题：有什么方法可以将wp_usermeta中的每个匹配行作为数组返回到我的一个结果对象中？所以var_dump()看起来像这样：

object(stdClass)#2906 (14) {
  ["user_id"]=>
  string(4) "5"
  ["firstname"]=>
  string(6) "Bilbo"
  ["lastname"]=>
  string(3) "Baggins"
  ...
  ["target_employer"]=>
  array(2) {
    [0]=>13,
    [1]=>53
  }
}

更新： @bpanulla：这是真实的（未简化的查询）......

"SELECT wsat_ib.user_id, wpjb_resume.firstname, wpjb_resume.lastname, wsat_ib.overall_score, wsat_ib.account_score, wsat_ib.econ_score, wsat_ib.math_score, wsat_ib.logic_score, wsat_ib.fsanaly_score, wsat_ib.corpval_score, wsat_ib.end_time, GROUP_CONCAT(wp_usermeta.meta_value) AS target_employers, wpjb_field_value.value AS school, wpjb_application.job_id
FROM  `wsat_ib` 
LEFT JOIN wp_usermeta ON wsat_ib.user_id = wp_usermeta.user_id
LEFT JOIN wpjb_resume ON wsat_ib.user_id = wpjb_resume.user_id
LEFT JOIN wpjb_field_value ON wpjb_resume.id=wpjb_field_value.job_id 
LEFT JOIN wpjb_application ON wpjb_application.user_id = wsat_ib.user_id AND wpjb_application.field_id=3
WHERE (wp_usermeta.meta_key =  'target_employer'
AND wp_usermeta.meta_value =  'public'
AND wpjb_resume.is_active =1)
GROUP BY user_id
";

Answer 1

我不认为MySQL可以将数组返回给PHP，但它可以使用GROUP_CONCAT aggregate function.返回分隔列表尝试类似：

SELECT user_id, firstname, lastname,
     GROUP_CONCAT(wp_usermeta.meta_value) as target_employer_id
FROM `wsat_ib` 
    LEFT JOIN wp_usermeta ON
        (wsat_ib.user_id = wp_usermeta.user_id
           AND wp_usermeta.meta_key = 'target_employer')
GROUP BY user_id, firstname, lastname

默认情况下，您应该在target_employer_id中获得以逗号分隔的元素列表。您可以使用PHP explode函数将其转换为PHP逻辑中的数组。

MySQL将某些结果组合成一个数组

1 个答案: