Question

我试过这样的

<script type="text/javascript">
     var date2=02/09/2009;
     var date1=03/12/2009;
     var diff = date1.getDate()-date2.getDate();
     alert (diff);

</script>

但它没有用，是getDate仅适用于Date的原因吗？

如何找到这两个日期之间的差异？我无法使用此功能，因为我在salesforce CRM apex页面中添加了javascript？

编辑1：事实上，这也无法正常工作

<script type="text/javascript">
     var date2= new Date ("02/09/2009");
     var date1= new Date ("04/09/2009");
     var diff = date1.getDate()-date2.getDate();
     alert (diff);

</script>

编辑2：它也不起作用......

<script type="text/javascript">
     var date2= "02/09/2009";
     var date1= "04/09/2009";
     var diff2 =    new Date(Date.parse("03/12/2009")-
                        Date.parse("02/09/2009")).toLocaleDateString();

// var new_date = new Date（1970,01,01）; // var diff3 = diff2.getDate（）; alert（diff2）;

</script>

Answer 1


<script language="JavaScript">
<!--
function dstrToUTC(ds) {
 var dsarr = ds.split("/");
 var mm = parseInt(dsarr[0],10);
 var dd = parseInt(dsarr[1],10);
 var yy = parseInt(dsarr[2],10);
 return Date.UTC(yy,mm-1,dd,0,0,0);
}

function datediff(ds1,ds2) {
 var d1 = dstrToUTC(ds1);
 var d2 = dstrToUTC(ds2);
 var oneday = 86400000;
 return (d2-d1) / oneday;
}

// test cases are below

var a; var b;

a = "01/09/1999";
b = "01/10/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "01/12/1999";
b = "01/19/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "01/19/1999";
b = "01/12/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "01/03/1999";
b = "01/13/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "04/30/1999";
b = "05/01/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "05/30/1999";
b = "06/01/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "02/28/1999";
b = "03/01/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "02/28/2000";
b = "03/01/2000";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "01/01/1999";
b = "12/31/1999";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "01/01/2000";
b = "12/31/2000";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

a = "12/15/1999";
b = "01/15/2001";
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>");

// -->
</script>

Answer 2

date2 = 02/09/2009不被视为日期。它以这种方式工作。首先它是02/09，它返回0.2222222222222222并且除以2009（0.2222222222222222/2009）。最后你得到了一个结果date2 = 0.0001106133510314695。以同样的方式计算date1的结果。

这不是有效的操作。如果要定义日期。确保您以正确的日期格式放置数据。

使用新的Date（）或Date.parse（“02/09/2009”）

修改

new Date(Date.parse("03/12/2009")-Date.parse("02/09/2009")).toLocaleDateString() Or new Date(date1- date2).toLocaleDateString()

不起作用.. ??

修改：

可能会有效..你能不能试试..

Date.parse("03/12/2009")-Date.parse("02/09/2009") / (24*60*60*1000)

它返回31天

它似乎对我有用..但在我的时区它花了03/12/2009作为第3个月的第11天和2009年

（24 * 60 * 60 * 1000）=每天的毫秒数

Answer 3

getDate是Date对象的方法。因为任何文档明确说明它返回0到31范围内的月份日期。如果不是同一个月，尝试从另一个中减去一个是没有意义的。

Answer 4

diff.setTime(Math.abs(date1.getTime() - date2.getTime()));

timediff = diff.getTime();

weeks = Math.floor(timediff / (1000 * 60 * 60 * 24 * 7));
timediff -= weeks * (1000 * 60 * 60 * 24 * 7);

days = Math.floor(timediff / (1000 * 60 * 60 * 24)); 
timediff -= days * (1000 * 60 * 60 * 24);

hours = Math.floor(timediff / (1000 * 60 * 60)); 
timediff -= hours * (1000 * 60 * 60);

mins = Math.floor(timediff / (1000 * 60)); 
timediff -= mins * (1000 * 60);

secs = Math.floor(timediff / 1000); 
timediff -= secs * 1000;

alert(weeks + " weeks, " + days + " days, " + hours + " hours, " + mins + " minutes, and " + secs + " seconds");

Answer 5

getDate（）返回日期月份，在你的情况下：9和12。
您应该通过以下方式明确定义日期对象。月份为0，因此0 = 1月，1 = 2月......

var date2 = new Date（2009,1,9）;
这些是数字，而不是字符串。如果您想使用字符串作为日期，那么您需要完全符合该格式，没有任何内容是可选的：

var newDate = new Date（“month day，year hours：minutes：seconds”）; var date2 = new Date（“2009年2月9日00:00:00”）;

<强> [编辑] 完整的解决方案，如果日期格式为mm / dd / yyyy，差异应以天为单位：

<script type="text/javascript">
    function daysFromString(dateString)
    {
        // split strings at / and return array
        var splittedString = dateString.split("/");
        // make a new date. Caveat: Months are 0-based in JS
        var newDate = new Date(parseInt(splittedString[2], 10), parseInt(splittedString[0], 10)-1, parseInt(splittedString[1], 10));
        // returns days since jan 1 1970
        return Math.round(newDate.getTime() / (24*3600*1000));
    }

    var dateString2 = "02/09/2009";
    var dateString1= "03/12/2009";
    var dateDays1 = daysFromString(dateString1);
    var dateDays2 = daysFromString(dateString2);
    var diff = dateDays1 - dateDays2;
    alert (diff);
</script>

Answer 6

使用Date.parse（date1） - Date.parse（date2）

Answer 7

Here解释了如何在javascript中找到两个日期之间的差异

Answer 8

是肯定的。您必须使用日期对象，例如

var d = new Date(2009,9,19); //19th october, months are 0-based
var d2 = new Date(2009,10,12);
var diff = (d2 - d)/60000;  //diff in minutes
alert(diff / 24);   //difference in hours

Answer 9

尝试

var diff2 =    Date.parse("03/12/2009") - Date.parse("02/09/2009");

它会以毫秒为单位显示日期之间的差异。将此数字除以86,400,000，差异将以天为单位。

Answer 10

<script type="text/javascript">
function GetD()
{
    var date1 = new Date ( 2009 , 09 , 02 );
    var date2 = new Date ( 2009 , 12 , 03 );        

    var diff = days_between (date1,date2);
    alert ( diff );
}
function days_between(date1, date2) {

    // The number of milliseconds in one day
    var ONE_DAY = 1000 * 60 * 60 * 24;

    // Convert both dates to milliseconds
    var date1_ms = date1.getTime();
    var date2_ms = date2.getTime();

    // Calculate the difference in milliseconds
    var difference_ms = Math.abs(date1_ms - date2_ms);

    // Convert back to days and return

    return Math.round(difference_ms/ONE_DAY);
}
</script>

计算两个日期之间的差异

10 个答案: