Question

我有以下XML文件

<lexicon>
<word>
  <base>a</base>
  <category>determiner</category>
  <id>E0006419</id>
</word>
<word>
  <base>abandon</base>
  <category>verb</category>
  <id>E0006429</id>
  <ditransitive/>
  <transitive/>
</word>
<word>
  <base>abbey</base>
  <category>noun</category>
  <id>E0203496</id>
</word>
<word>
  <base>ability</base>
  <category>noun</category>
  <id>E0006490</id>
</word>
<word>
  <base>able</base>
  <category>adjective</category>
  <id>E0006510</id>
  <predicative/>
  <qualitative/>
</word>
<word>
  <base>abnormal</base>
  <category>adjective</category>
  <id>E0006517</id>
  <predicative/>
  <qualitative/>
</word>
<word>
  <base>abolish</base>
  <category>verb</category>
  <id>E0006524</id>
  <transitive/>
</word>
</lexicon>

我需要使用C＃应用程序阅读此文件，如果只有category是verb，我想打印整个元素word。
我怎么能这样做？

Answer 1

您可以将linq用于xml。

    var xmlStr = File.ReadAllText("fileName.xml");


    var str = XElement.Parse(xmlStr);

    var result = str.Elements("word").
Where(x => x.Element("category").Value.Equals("verb")).ToList();

    Console.WriteLine(result);

Answer 2

您也可以使用XPath。有点老式但仍然有效：

using System.Xml;

...

XmlDocument xmlDocument;

xmlDocument = new XmlDocument();
xmlDocument.LoadXml(xml);

foreach (XmlElement xmlElement in 
    xmlDocument.DocumentElement.SelectNodes("word[category='verb']"))
{
    Console.Out.WriteLine(xmlElement.OuterXml);
}

Answer 3

我就是这样做的（下面的代码已经过测试，下面提供了完整的源代码），首先创建一个具有共同属性的类

    class Word
    {
        public string Base { get; set; }
        public string Category { get; set; }
        public string Id { get; set; }
    }

使用带有INPUT_DATA的XDocument加载以进行演示，并使用 lexicon 查找元素名称。。

    XDocument doc = XDocument.Parse(INPUT_DATA);
    XElement lex = doc.Element("lexicon");

确保有值并使用linq从中提取单词元素。。

    Word[] catWords = null;
    if (lex != null)
    {
        IEnumerable<XElement> words = lex.Elements("word");
        catWords = (from itm in words
                    where itm.Element("category") != null
                        && itm.Element("category").Value == "verb"
                        && itm.Element("id") != null
                        && itm.Element("base") != null
                    select new Word() 
                    {
                        Base = itm.Element("base").Value,
                        Category = itm.Element("category").Value,
                        Id = itm.Element("id").Value,
                    }).ToArray<Word>();
    }

where语句检查类别元素是否存在以及类别值是否为null，然后再次检查它是否为动词。然后检查其他节点是否也存在。。

linq查询将返回IEnumerable＆lt;类型名称＆gt;对象，所以我们可以调用ToArray＆lt;使用Typename＆gt;（）将整个集合强制转换为我们想要的类型。

然后将其打印出来。。。

[Found]
 Id: E0006429
 Base: abandon
 Category: verb

[Found]
 Id: E0006524
 Base: abolish
 Category: verb

完整来源：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Xml.Linq;

namespace test
{
    class Program
    {

        class Word
        {
            public string Base { get; set; }
            public string Category { get; set; }
            public string Id { get; set; }
        }

        static void Main(string[] args)
        {
            XDocument doc = XDocument.Parse(INPUT_DATA);
            XElement lex = doc.Element("lexicon");
            Word[] catWords = null;
            if (lex != null)
            {
                IEnumerable<XElement> words = lex.Elements("word");
                catWords = (from itm in words
                            where itm.Element("category") != null
                                && itm.Element("category").Value == "verb"
                                && itm.Element("id") != null
                                && itm.Element("base") != null
                            select new Word() 
                            {
                                Base = itm.Element("base").Value,
                                Category = itm.Element("category").Value,
                                Id = itm.Element("id").Value,
                            }).ToArray<Word>();
            }

            //print it
            if (catWords != null)
            {
                Console.WriteLine("Words with <category> and value verb:\n");
                foreach (Word itm in catWords)
                    Console.WriteLine("[Found]\n Id: {0}\n Base: {1}\n Category: {2}\n", 
                        itm.Id, itm.Base, itm.Category);
            }
        }

        const string INPUT_DATA =
        @"<?xml version=""1.0""?>
        <lexicon>
        <word>
          <base>a</base>
          <category>determiner</category>
          <id>E0006419</id>
        </word>
        <word>
          <base>abandon</base>
          <category>verb</category>
          <id>E0006429</id>
          <ditransitive/>
          <transitive/>
        </word>
        <word>
          <base>abbey</base>
          <category>noun</category>
          <id>E0203496</id>
        </word>
        <word>
          <base>ability</base>
          <category>noun</category>
          <id>E0006490</id>
        </word>
        <word>
          <base>able</base>
          <category>adjective</category>
          <id>E0006510</id>
          <predicative/>
          <qualitative/>
        </word>
        <word>
          <base>abnormal</base>
          <category>adjective</category>
          <id>E0006517</id>
          <predicative/>
          <qualitative/>
        </word>
        <word>
          <base>abolish</base>
          <category>verb</category>
          <id>E0006524</id>
          <transitive/>
        </word>
        </lexicon>";

    }
}

Answer 4

XDocument xdoc = XDocument.Load(path_to_xml);
var word = xdoc.Elements("word")
               .SingleOrDefault(w => (string)w.Element("category") == "verb");

This query将返回整个字XElement。如果有多个类别verb的单词元素，则会获得InvalidOperationException。如果没有类别为verb的元素，则结果为null。

Answer 5

或者，您可以通过XPath方法使用XPathSelectElements查询：

var document = XDocument.Parse(yourXmlAsString);
var words = document.XPathSelectElements("//word[./category[text() = 'verb']]");

从XML文件中读取特定的XML元素

5 个答案: